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motikmotik
2 years ago
8

Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we

aring a g-suit can withstand accelerations up to about 9g (88.2 m/s2) without losing consciousness.
(a) If a human centrifuge has a radius of 4.00 m, what angular speed (in rad/s) results in a centripetal acceleration of 9g?
_______rad/s

(b) What linear speed (in m/s) would a person in the centrifuge have at this acceleration?
________m/s

Physics
1 answer:
Andreyy892 years ago
6 0

(a) The angular speed of the human centrifuge is 4.7 rad/s.

(b) The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

<h3>Angular speed of the human centrifuge</h3>

a = ω²r

where;

  • a is centripetal acceleration = 9g
  • r is radius of human centrifuge

ω = √(a/r)

ω = √(9g/r)

ω = √(9 x 9.8 / 4)

ω = 4.7 rad/s

<h3>Linear speed of the centrifuge </h3>

v = ωr

where;

  • v is linear speed

v = (4.7 rad/s) x 4 m

v = 18.8 m/s

Thus, the angular speed of the human centrifuge is 4.7 rad/s. The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

Learn more about angular speed here: brainly.com/question/6860269

#SPJ1

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Answer:

  r = 3.787 10¹¹ m

Explanation:

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     T = 1.03 10⁸ s

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The acceleration of the charge is 1.07 × 10²⁸ m/s². It is obtained as the force per unit mass of the charge.

<h3>What is Columb's law?</h3>

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

The electric force is found as;

\rm F = \frac{Kq_1q_2}{r^2} \\\\ F= \frac{9 \times 10^9 \times( 3.2 \times 10^{-19})^2}{(3.60 \times 10^{-15})^2}\\\\ F=71.1 \ N

The acceleration of the charge is found as;

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Hence,the acceleration of the charge is 1.07 × 10²⁸ m/s².

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