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motikmotik
2 years ago
8

Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we

aring a g-suit can withstand accelerations up to about 9g (88.2 m/s2) without losing consciousness.
(a) If a human centrifuge has a radius of 4.00 m, what angular speed (in rad/s) results in a centripetal acceleration of 9g?
_______rad/s

(b) What linear speed (in m/s) would a person in the centrifuge have at this acceleration?
________m/s

Physics
1 answer:
Andreyy892 years ago
6 0

(a) The angular speed of the human centrifuge is 4.7 rad/s.

(b) The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

<h3>Angular speed of the human centrifuge</h3>

a = ω²r

where;

  • a is centripetal acceleration = 9g
  • r is radius of human centrifuge

ω = √(a/r)

ω = √(9g/r)

ω = √(9 x 9.8 / 4)

ω = 4.7 rad/s

<h3>Linear speed of the centrifuge </h3>

v = ωr

where;

  • v is linear speed

v = (4.7 rad/s) x 4 m

v = 18.8 m/s

Thus, the angular speed of the human centrifuge is 4.7 rad/s. The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

Learn more about angular speed here: brainly.com/question/6860269

#SPJ1

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A 25,000-kg train car moving at 2.50 m/s collides with and connects to a train car of equal mass moving in the same direction at
Margarita [4]

Answer:

14062.5 J

Explanation:

From the law of conservation of momentum,

Total momentum before collision  = Total momentum after collision.

V = (m₁u₁ + m₂u₂)/(m₁+m₂).................1

Where V = common velocity after collision

Given: m₁ = m₂ = 25000 kg, u₁ = 2.5 m/s, u₂ = 1 m/s

Substitute into equation 1

V = [25000(2.5) + 25000(1)]/(25000+25000)

V = (62500+25000)/50000

V = 87500/50000

V = 1.75 m/s.

Note: The collision is an inelastic collision as such there is lost in kinetic energy of the system.

Total Kinetic energy before collision = kinetic energy of the first train car + kinetic energy of the second train car

E₁ = 1/2m₁u₁² + 1/2m₂u₂²........................ Equation 2

Where E₁ = Total kinetic energy of the body before collision, m₁ and m₂ = mass of the first train car and second train car respectively. u₁ and u₂ = initial velocity of the first train car and second train car respectively.

Given: m₁ = m₂ = 25000 kg, u₁ = 2.5 m/s, u₂ = 1 m/s

Substitute into equation 2

E₁ = 1/2(25000)(2.5)² + 1/2(25000)(1.0)²

E₁ = 12500(6.25) + 12500

E₁ = 78125+12500

E₁ = 90625 J.

Also

E₂ = 1/2V²(m₁+m₂)....................... Equation 3

Where E₂ = total kinetic energy of the system after collision, V = common velocity, m₁ and m₂ = mass of the first and second train car respectively.

Given: V = 1.75 m/s, m₁ = m₂ = 25000 kg

Substitute into equation 3

E₂ = 1/2(1.75)²(25000+25000)

E₂ = 1/2(3.0625)(50000)

E₂ = (3.0625)(25000)

E₂ = 76562.5 J.

Lost in kinetic Energy of the system = E₁ - E₂ = 90625 - 76562.5

Lost in kinetic energy of the system = 14062.5 J

5 0
3 years ago
If a dog is running at 4.38 m/s for 37.34 seconds, how far will it go?
sdas [7]

Answer:

163.5m

this is how far the doggo would go

(In theory)

If I'm wrong I apologize

7 0
3 years ago
A baseball is thrown 50.0m in 3.0s, what is the average speed of the baseball? Calculated answer is 16.666667! What is the corre
castortr0y [4]

Answer:

20m/s

Explanation:

Given parameters:

Distance of throw = 50m

Time  = 3s

Unknown:

Average speed  = ?

Solution:

Average speed is distance divided by time;

  Average speed  = \frac{distance }{time}

Insert the parameters and solve;

  Average speed  = \frac{50}{3}   = 16.66667m/s  = 20m/s

5 0
3 years ago
Ear wax, which is produced in the external auditory canal, contains chemicals that guard the ear from infections. TRUE OR FALSE
kobusy [5.1K]
The answer is true not false if the ear gets infection it makes more wax so the infection will clear out of the ear 
5 0
3 years ago
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A wall, acted upon by a force of 20 N, does not move. The work done on the wall in this process is
jenyasd209 [6]

Answer:

0 (Zero)

Explanation:

Definition of work done states that ,

Work done on an object is the force applied on that object in the direction of Displacement of the object .

means that ,

W = F.dS (Dot product of Force and displacement)

When the wall is acted upon by the force of 20 N , Wall does not move ,

Thus , displacement of the wall is zero.

So, W = 20×0 = 0.

Thus, Work done on the wall is zero.

8 0
3 years ago
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