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motikmotik
2 years ago
8

Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we

aring a g-suit can withstand accelerations up to about 9g (88.2 m/s2) without losing consciousness.
(a) If a human centrifuge has a radius of 4.00 m, what angular speed (in rad/s) results in a centripetal acceleration of 9g?
_______rad/s

(b) What linear speed (in m/s) would a person in the centrifuge have at this acceleration?
________m/s

Physics
1 answer:
Andreyy892 years ago
6 0

(a) The angular speed of the human centrifuge is 4.7 rad/s.

(b) The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

<h3>Angular speed of the human centrifuge</h3>

a = ω²r

where;

  • a is centripetal acceleration = 9g
  • r is radius of human centrifuge

ω = √(a/r)

ω = √(9g/r)

ω = √(9 x 9.8 / 4)

ω = 4.7 rad/s

<h3>Linear speed of the centrifuge </h3>

v = ωr

where;

  • v is linear speed

v = (4.7 rad/s) x 4 m

v = 18.8 m/s

Thus, the angular speed of the human centrifuge is 4.7 rad/s. The linear speed (in m/s)  a person in the centrifuge would have at this is 18.8 m/s.

Learn more about angular speed here: brainly.com/question/6860269

#SPJ1

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Problem 21-40a:
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Answer:

Part a)

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

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Explanation:

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F = qE

here we have

q = 1.6 \times 10^{-19}C

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now force is given as

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F_g = (9.1 \times 10^{-31})(9.81) = 8.93 \times 10^[-30} N

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\frac{F_e}{F_g} = \frac{2.45 \times 10^{-17}}{8.93 \times 10^{-30}}

\frac{F_e}{F_g} = 2.74 \times 10^{12}

Part b)

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