Answer:
Explanation:
The volume of a sphere is:
V = 4/3 * π * a^3
The volume charge density would then be:
p = Q/V
p = 3*Q/(4 * π * a^3)
If the charge density depends on the radius:
p = f(r) = k * r
I integrate the charge density in spherical coordinates. The charge density integrated in the whole volume is equal to total charge.





Since p = k*r
Q = p*π^2*r^3 / 2
Then:
p(r) = 2*Q / (π^2*r^3)
Answer:
The trains mass in pounds would be 40084.029 if you would round it to the hundreths
Explanation:
The correct expression for the maximum speed of the object during its motion is
.
<h3>
Maximum speed of the object</h3>
The maximum speed of the object is determined using the following formulas;
v(max) = Aω
where;
- A is the amplitude of the motion
- ω is angular speed
The maximum speed of the object can also be obtained from the maximum net force on the object,
F = ma
where;
- F is the maximum net force
- a is the acceleration
- m is mass of the object
F = m(v/t)
mv = Ft
v = Ft/m
Thus, the correct expression for the maximum speed of the object during its motion is
.
Learn more about maximum speed here: brainly.com/question/4931057
Answer:

Explanation:
The question, translated, is:
- <em>A steel ball rolls and falls off the edge of a table from 4ft above the floor. If you hit the ground 5ft from the base of the table, what was your initial horizontal velocity?</em>
<em />
<h2>Solution</h2>
<em />
This is a projectile motion, for which, the equations that you will need are:


<u />
<u>1. Calculate the time that it takes the ball to fall 4ft</u>

<u />
<u>2. Calculate the horizontal velocity:</u>

10 cm3 because the density equition is d = m/v