To get the answer to this equation you first cancel out the 6! ;)
(x^2-1)(6x-1) / (x+1)
Then rewrite x^2-1 in the form a^2 + b^2, where a=x and b=1
(x^2-1^2)(6x-1) / (x+1)
Then use the difference of squares!
(x+1)(x-1)(6x-1) / (x+1)
LASTLY cancel "x+1" !
so ur answer is (x-1) (6x-1)
That makes the correct answer to this problem answer choice (D) (x-1) (6x-1)
YW!!! ;)
By using <span>De Moivre's theorem:
</span>
If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴
![\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bz%7D%20%3D%20%20%5Csqrt%5Bn%5D%7Ba%7D%20%5C%20%28cos%20%5C%20%20%5Cfrac%7B%5Ctheta%20%2B%20360K%7D%7Bn%7D%20%2B%20i%20%5C%20sin%20%5C%20%5Cfrac%7B%5Ctheta%20%2B360k%7D%7Bn%7D%20%29)
k= 0, 1 , 2, ..... , (n-1)
For The given complex number <span>⇒ z = 81(cos(3π/8) + i sin(3π/8))
</span>
Part (A) <span>
find the modulus for all of the fourth roots </span>
<span>∴ The modulus of the given complex number = l z l = 81
</span>
∴ The modulus of the fourth root =
Part (b) find the angle for each of the four roots
The angle of the given complex number =

There is four roots and the angle between each root =

The angle of the first root =

The angle of the second root =

The angle of the third root =

The angle of the fourth root =
Part (C): find all of the fourth roots of this
The first root =

The second root =

The third root =

The fourth root =
Answer:
(x + 2)² + (y + 9)² = 49
Step-by-step explanation:
Equation:
(x - h)² + (y - k)² = r²
(x - -2)² + (y - -9)² = 7²
(x + 2)² + (y + 9)² = 49
Answer:£22.50
Step-by-step explanation:
£15x7=£105
285-105= 180 : 8= £22.50p
3. A
4.B
5.B
Very happy to help you!