1. Determine the amount concentration of calcium ions and acetate ions in a 0.80 mol/L

Chemistry

1 answer:

PIT_PIT [208]1 year ago

6 0

Since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

<h3>What is concentration?</h3>

The term concentration has to do with the amount of substance in solution. The concentration can be measured in several units. Generally, concentration is expressed in molarity, molality, mass concentration units or percentage.

Now we are asked to find the amount concentration of calcium ions and acetate ions in a 0.80 mol/L solution of calcium acetate. The formula of calcium acetate is Ca(CH3COO)2.

Thus;

Ca(CH3COO)2(aq) ----> Ca^2+(aq) + 2CH3COO^-(aq)

It then follows that since there is one mole of Ca^2+ in calcium acetate, its concentration is 0.80 mol/L.

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