Answer:
1
Explanation:
in my opinion,The answer would be organism
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Answer:
Since molarity is defined as moles of solute per liter of solution, we need to find the number of moles of nitric acid, and the volume of solution.
molar mass of nitric acid (HNO3) = 1 + 14 + (3x16) = 15 + 48 = 63 g/mole
1.50 g/ml x 1000 ml = 1500 g/liter
1500 g/liter x 0.90 = 1350 g/liter of pure HNO3 (the 0.9 is to correct for the fact that it is 90% pure)
1350 g/liter x 1 mole/63 g = 21.43 moles/liter = 21 Molar HNO3
= 21 Molar of HNO3
Answer: The precipitate formed is 
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid or precipitated form are represented by (s) after their chemical formulas.
A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.
The balanced chemical equation is:
Answer:
3.33 M
Explanation:
It seems your question is incomplete, however, that same fragment has been found somewhere else in the web:
" <em>A chemist prepares a solution of silver nitrate (AgNO3) by measuring out 85.g of silver nitrate into a 150.mL volumetric flask and filling the flask to the mark with water.</em>
<em>Calculate the concentration in mol/L of the chemist's silver nitrate solution. Be sure your answer has the correct number of significant digits.</em> "
In this case, first we <u>calculate the moles of AgNO₃</u>, using its molecular weight:
- 85.0 g AgNO₃ ÷ 169.87 g/mol = 0.500 mol AgNO₃
Then we<u> convert the 150 mL of the volumetric flask into L</u>:
Finally we <u>divide the moles by the volume</u>:
- 0.500 mol AgNO₃ / 0.150 L = 3.33 M
Answer:- Atomic number for sulfur is 16 and it's electron configuration is 
. Here, there are total for electrons in 3p and the set of quantum numbers for these 4 electrons would be as..
For the first electron of 3p-
n = 3, l = 1, ml = -1 and ms = +(1/2)
for the second electron of 3p-
n = 3, l = 1, ml = 0 and ms = +(1/2)
for the third electron of 3p-
n = 3, l = 1, ml = +1 and ms = +(1/2)
and for the fourth electron of 3p-
n = 3, l = 1, ml = -1 and ms = -(1/2)
