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Ratling [72]
2 years ago
13

A variable capacitor with a range from 12 to 279 pF is used with a coil to form a variable-frequency LC circuit to tune the inpu

t to a radio. (a) What is the ratio of maximum frequency to minimum frequency that can be obtained with such a capacitor
Physics
1 answer:
DiKsa [7]2 years ago
3 0

The ratio of maximum frequency and minimum frequency is 4.9.

<h3>Calculation:</h3>

The relation between frequency, f, and conductance, C and inductance, L is given as:

f = \frac{1}{2\pi \sqrt{LC} }

Given,

Cmax = 279 pF

Cmin = 12 pF

The smaller value of C gives the the larger value of f, therefore,

fmax = \frac{1}{2\pi\sqrt{LCmin}  }           ....(1)

fmin = \frac{1}{2\pi\sqrt{LCmax}  }           .....(2)

Dividing both the equations (1) and (2):

\frac{fmax}{fmin} =\frac{\sqrt{Cmax} }{\sqrt{Cmin} }

\frac{fmax}{fmin} = \frac{\sqrt{279} }{\sqrt{12} }

        = 4.9

Hence, the ratio of maximum to minimum frequency is 4.9.

Learn more about the frequency calculation here:

brainly.com/question/18650584

#SPJ4

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