Help help help plzzz. A 15-kilogram wagon originally at rest on a level road is pulled by a rope that exerts a constant horizont
1 answer:
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Answer:
<em>Speed of the electron is 2.46 x 10^8 m/s</em>
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Explanation:
momentum of the electron before relativistic effect =
where is the rest mass of the electron
V is the velocity of the electron.
under relativistic effect, the mass increases.
under relativistic effect, the new mass M will be
M =
where
c is the speed of light = 3 x 10^8 m/s
V is the speed with which the electron travels.
The new momentum will therefore be
==>
It is stated that the relativistic momentum is 1.75 times the non-relativistic momentum. Equating, we have
1.75 =
the equation reduces to
1.75 =
square both sides of the equation, we have
3.0625 = 1/
3.0625 - 3.0625 = 1
2.0625 = 3.0625
= 0.67
β = 0.819
substitute for
V/c = 0.819
V = c x 0.819
V = 3 x 10^8 x 0.819 = <em>2.46 x 10^8 m/s</em>
Answer:
The minimum distance in which the car will stop is
x=167.38m
Explanation:
∑F=m*a
∑F=u*m*g
The force of friction is the same value but in different direction of the force moving the car so it can stop so