Answer:
166.8 m
30.18 m/s
Explanation:
u = Velocidad inicial del automóvil = 120 km/h =
v = Velocidad final = 0
s = Desplazamiento
a = Aceleración
t = Tiempo tomado = 10 s
De las ecuaciones cinemáticas de movimiento tenemos
La distancia que tarda el automóvil en detenerse es 166.8 m
Ahora s = 30 m
La velocidad a la que el otro automóvil sería golpeado es 30.18 m/s.
Answer:
the atom number
Explanation:
atoms are determend by the numbers of protons in their core, as the number of protons determines what type of element the atom will be (noble gasses, Alkali Metals, Other Metals) and the atom number involves both protons and neutrons
Also spelling may be bad, as Grammarly dosen't work with brainly at all. and if its right brainlist plz (´~`ヾ)
The answer is <span>A) Velocity describes speed with direction.
Speed can be in any direction </span>
Answer: Acceleration = 5m/s^2; Distance traveled = 320 m
Explanation:
Velocity of car = 40m/s
Time taken = 8 seconds
Acceleration = ?
Distance traveled = ?
A) Since acceleration is the rate of change of velocity per unit time
i.e acceleration = velocity / time
acceleration = 40m/s / 8 seconds
Acceleration = 5m/s^2
B) To get how far the car traveled before stopping, obtain the distance from the formula:
velocity = distance traveled / time
40m/s = distance / 8 seconds
Distance = 40m/s x 8 seconds
Distance = 320 m
Thus, the car’s acceleration is 5m/s^2 while it traveled 320 metres before stopping.