Motion is...

After the discovery of Uranus, astronomers calculated its orbit and predicted its position in the sky using Kepler's laws of pla

Softa [21]

Answer:

a. verify that your observations are correct

c. think about what else might cause the observed discrepancy

Explanation:

Let's begin by explaining that a law is an affirmation (something established) based on repeated long-term observation of a phenomenon that has been studied and verified.

That is: A law is present in all known theories and therefore is considered universal. In addition, <u>a law can not be refuted, nor changed, because its precepts have been proven through various studies.</u>

Then, based on what is explained above, Kepler's laws of planetary motion exist because they were rigorously tested and verified, therefore they can not be refuted.

So, if we have a small discrepancy between the predicted and actual positions of Uranus after using Kepler's laws, we have to verify carefully our observations again and search what might be causing that discrepancy. But we cannot assume Kepler's Laws are incorrecto or need modifications.

In addition, we cannot consider that Uranus may not be a planet, because the discrepancy is small. In fact, this discrepancy lead to the discovery of another planet, Neptune.

7 0

3 years ago

3. According to the National Automobile Dealers Association, a single dealership may employ people with as many as 57 different

weeeeeb [17]

I think it might just be c because that is the only reasonable option

4 0

3 years ago

Read 2 more answers

in a collusion, a 15 kg object moving with a velocity of 3 m/s transfers all of its momentum to a 5 kg object. what would be the

Hunter-Best [27]

According to momentum conservation
15*3 = 45kgm/s
and the velocity of 5 kg mass will be
45/5 = 9 m/s

7 0

3 years ago

Read 2 more answers

Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th

DiKsa [7]

Answer:

a. $\rm -1.49\ m/s^2.$

b. $\rm 50.49\ m.$

Explanation:

<u>Given:</u>

Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

$\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).$

At time t = 3 seconds,

$\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.$

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

$\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.$

For the time interval of 2 seconds,

$\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt$

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

$\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.$

It is the displacement of the particle in 2 seconds.

7 0

4 years ago

The first-order decomposition of cyclopropane has a rate constant of 6.7 × 10–4 s–1. If the initial concentration of cyclopropan

Ket [755]

Answer:

.864 M

Explanation:

For first order decomposition,

rate constant k = 1/t x ln a / (a - x )

given , a = 1.33 M , t = 644 s , k = 6.7 x 10⁻⁴ , a - x = ? = b( let )

6.7 x 10 ⁻⁴ = 1/644 x ln 1.33/b

ln 1.33/b = 6.7 x 10⁻⁴ x 644 = .4315

1.33 / b = e⁰ ⁴³¹⁵ = 1.5395

b = 1.33 / 1.5395 = .864 M.

7 0

4 years ago