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4 years ago

How do you rearrange the terms in the equation for kinetic energy to solve for velocity?

Physics

2 answers:

Andreas93 [3]4 years ago

7 0

Answer:

KE ÷ (1/2 x m) = V² Which can be rewritten as V² = KE ÷ (1/2 x m)

Explanation:

To make V² the subject we have to get rid of everything other than V² on the right side of the equation. To do this we use simple algbra rules (it is recommended to get familar with algbra in physics).

Since 0.5 (1/2) is times-ed by mass we can undo this by dividing (since divided by is opposide of times and removes it from the right side.

Now on the left side you have KE ÷ (0.5 x m) = V² remember to use brackets pretty much everytime you do an equation in physics that has more than one operation since it's safer.

And finally remember to square root the answer you get since that will be V².

If this isn't very clear (I'm not very good at explaining alebra) I recommend learning more about it since you will have to use algbra in physics a lot. Some scientific calculators also some with solver which can figure out unknowns for you.

Jobisdone [24]4 years ago

5 0

-- Multiply each side of the equation by 2.

-- Divide each side by ' m '.

-- Take the square root of each side.

V = √(2•KE/m)

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A pole AB of length 10.0m and weight 600N has its center of gravity 4.0m from the end A, and lies on horizontal ground .Calculat

postnew [5]

Answer:

The force required to begin to lift the pole from the end 'A' is 240 N

Explanation:

The given parameters for the pole AB are;

The length of the pole, l = 10.0 m

The weight of the pole, W = 600 N ↓

The distance of the center of gravity of the pole from the side 'A' = 4.0 m

Let ' $F_A$ ' represent the force required to begin to lift the pole from the end 'A' and let a force applied in the upwards direction be positive

For equilibrium, the sum of moment about the point 'B' = 0, therefore, taking moment about 'B', we have

$F_A$ × 10.0 m - W × 4.0 m = 0

∴ $F_A$ × 10.0 m = W × 4.0 m = 600 N × 4.0 m

$F_A$ × 10.0 m = 600 N × 4.0 m

∴ $F_A$ = 600 N × 4.0 m/(10.0 m) = 240 N

The force required to begin to lift the pole from the end 'A', $F_A$ = 240 N.

8 0

3 years ago

Two cars have identical horns, each emitting a frequency of fs = 406 Hz. One of the cars is moving with a speed of 10.5 m/s towa

Archy [21]

Answer:

$f_{B}=12.8 Hz$

Explanation:

Let's start finding the frequency heard by the bystander due to the moving car. We need to use Doppler effect here:

$f_{obs}=f_{s}\left(\frac{v}{v-v_{car}}\right)$

v is the speed of sound (v = 343 m/s)

So, we have:

$f_{obs}=406\left(\frac{343}{343-10.5}\right)=418.8 Hz$

Now, the beat frequency heard by the bystander is the combine of the frequencies, it means the difference between them. Therefore the equation is given by:

$f_{B}=f_{obs}-f_{s}=418.8-406=12.8 Hz$

I hope it helps you!

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3 years ago

What is the momentum of a 65kg ball rolling at 5 m/s?

mojhsa [17]

Explanation:

Momentum = mass × velocity

p = (65 kg) (5 m/s)

p = 325 kg m/s

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3 years ago

Oil of SG = 0.87 and a kinematic viscosity v = 2.2 ' 10-4 m2/s flows through the vertical pipe shown in Fig. P8.25 at a rate of

LenKa [72]

Check the attached file for the solution

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3 years ago

If a machine exerts a force of 250 N on an object and no work is done, what must have occurred?

valina [46]

Answer:

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Explanation:

1) As we know that the work done is the product of force and displacement

It is given as

$W = Fdcos\theta$