Answer:
The velocities of each ball are
Explanation:
Using the conservation of momentum to find the velocity of each balls after the collision
Here have one equation but have two variable don't know so
Now have two equations and two variables so solving using
a) create an expression
for the ball's initial horizontal velocity, V0x, in terms of the variables
given in the problem statement.
v0x = vf * cos(Θf)
<span>
b) calculate the ball's initial vertical velocity, V0y, in
m/s</span>
v0x = 32.4m/s * cos(-25.5º)
= 29.2 m/s <span>
tanΘ = v1y / v0x → tan(-25.5) = v1y / 29.2m/s → v1y = -13.93
m/s
the vertical velocity when the ball was caught.
(v0y)² = (v1y)² + 2as = (-13.93m/s)² + 2 * 9.8m/s² * 5.5m = 301.78
m²/s²
v0y = 17.37 m/s
c) calculate the magnitude of the ball's initial velocity,
v0, in m/s</span>
v0 = sqrt (v0y^2 +
v0x^2)
v0 = sqrt (17.37^2 + 29.2^2)
m/s
v0 = 33.98 m/s
<span>
d) find the angle, theta0, in degrees above the horizontal at
which which the ball left the bat.</span>
tan Θ = v0y/v0x
<span>Θ = arctan(17.37/29.2) =
30.75º above horizontal</span>
Answer:
A sonar device sends pulses of sound waves down through the water. When these pulses hit objects like fish, vegetation or the bottom, they are reflected back to the surface. The sonar device measures how long it takes for the sound wave to travel down, hit an object and then bounce back up.
Answer:
the property of absorbing light of short wavelength and emitting light of longer wavelength.
Explanation:
YW
Answer:
Explanation:
Note : the questions do not come in the right order.
Data:
Mass = 0.0518kg
Velocity = 45 m / s
Distance (s) = 0.44m
C) what's the acceleration on the ball?
Using equation of motion,
V² = u² + 2as
V² - u² = 2as
a = (v² - u²) / 2s
a = (45² - 0) / 2 * 0.44 [the ball was at rest]
a = 2025 / 0.88
a = 2301.136m/s²
D) The net force on the ball?
Force = mass * acceleration
F = m*a
F = 0.0518 * 2301.136
F = 119.199N
The force acting on the ball was 133.465N
F = 133.47N
b) time period the ball was struck.
From the relationship between impulse and momentum,
Ft = m * v
133.47 * t = 0.058 * 45
t = 2.61 / 133.47
t = 0.01955s
a) average velocity (V) = total distance covered / total time taken
V = s / t
V = 0.44 / 0.01955
V = 22.50m/s.
e) if the ball was heavier and still experienced the same velocity, the applied would've been lesser than before.