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sammy [17]
3 years ago
9

A track star runs 100 meters in 10 seconds. What is the star's average speed?

Physics
2 answers:
Ksju [112]3 years ago
8 0

Answer:

10m/s

Explanation:

Maslowich3 years ago
6 0

Answer: 10

Explanation: Because, 10*10= 100 or 100/10=10

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if v=5.00 meters/second and makes an angle of 60 degrees with the negative direction of the y-axis, calculate the possible value
lora16 [44]

The answer is both 5sin(60)=4.33 and -5sin(60)=-4.33

5 0
4 years ago
Read 2 more answers
If you kick a ball and the ball accelerates through the air, the forces involved must be
wariber [46]
It would be kinetic and potential energy, potential from the force of the kick, and kinetic from energy exerted.
7 0
3 years ago
1) A person riding their bike on a nice cloudy day travels 50 meters in 20 seconds.
Rasek [7]

Answer:

5.59

Explanation:

50 meters in 10 seconds is 11.18, which is an easy way to remember. Just divided by 2

5 0
3 years ago
Before beginning an experiment Mrs. Wilson warns her science class not to drop the bar magnets on the floor what is the most lik
Ainat [17]

Answer:

They could lose their magnetism if they are dropped too hard or banging against something (the ground)

Explanation:

the domains may bump out of alignment. hope this helps ! :)

7 0
3 years ago
For a railgun, determine the current required to accelerate a 1000kg space vehicle to earths escape velocity on 10km of track wi
Troyanec [42]

Answer:

the current is 15.68 × 10^{5} A

Explanation:

mass = 1000 kg

magnetic fied = 2T

rail separation = 2m

escape velocity is 11.2km/s  = 11.2 × 10^{3} m/s

distance = 10 km = 10^{4} m

to find out

determine the current

solution

we know force F = I×L×B

here I is current and L is rail separation and B is magnetic field

so F = I ×2×2  = 4 I

so

acceleration is a = \frac{F}{mass}

a =  \frac{4I}{1000} m/s²

so equation of motion

v²-u² = 2 a S

here u is initial velocity and S is distance and a is acceleration and v is final velocity

11.2 × 10^{3} - 0 = 2×  \frac{4I}{1000} × 10^{4}

solve we get I

I = 15.68 × 10^{5} A

so the current is 15.68 × 10^{5} A

4 0
3 years ago
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