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netineya [11]
2 years ago
12

You deposit $2000 each year into an account earning 7% interest compounded annually. How much will you have in the account in 30

years?
Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
8 0

The amount that will be in the account after 30 years is $188,921.57.

<h3>How much would be in the account after 30 years?</h3>

When an amount is compounded annually, it means that once a year, the amount invested and the interest already accrued increases in value. Compound interest leads to a higher value of deposit when compared with simple interest, where only the amount deposited increases in value once a year.

The formula that can be used to determine the future value of the deposit in 30 years is : annuity factor x yearly deposit

Annuity factor = {[(1+r)^n] - 1} / r

Where:

  • r = interest rate
  • n = number of years

$2000 x [{(1.07^30) - 1} / 0.07] = $188,921.57

To learn more about calculating the future value of an annuity, please check: brainly.com/question/24108530

#SPJ1

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PB is a line segment on a number line. It has endpoints at -2 and 12. What is the coordinate of its midpoint.
Zielflug [23.3K]
It is 7
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5 0
3 years ago
For f(x)=log(the 2 is below log)2(x), between which two integers does f(40) lie?
Veronika [31]

f(x) = log2 x

f(40) = log2 40

40 = 2^y

2^5 = 32 and 2^6 = 64

so f(40) lies between  integers 5 and 6.

4 0
3 years ago
Find LCM of:<br><br>x2 - 9, 3x3 + 81​
VikaD [51]

Answer:

\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}

Step-by-step explanation:

Given two expressions ,

\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

<u>Factorising</u><u> </u><u>x²</u><u> </u><u>-</u><u> </u><u>9</u><u> </u><u>:</u><u>-</u><u> </u>

= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]

<u>Factorising</u><u> </u><u>3x</u><u>³</u><u> </u><u>+</u><u> </u><u>8</u><u>1</u><u> </u>

= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }

Hence we can see that (x+3) is common factor in both expressions.

<u>Hence</u><u> </u><u>the</u><u> </u><u>LCM</u><u> </u><u>is</u><u> </u><u>(</u><u> </u><u>x</u><u>+</u><u>3</u><u> </u><u>)</u><u> </u><u>.</u>

8 0
3 years ago
The benchmark used to compare 9/8 and 11/12
olga nikolaevna [1]

Answer:

99/96

i hope is the answer


Step-by-step explanation:


7 0
4 years ago
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The reaction of the body to a dose of medicine can sometimes be represented by an equation of the formR = M^2 (C/2- M/3),where C
mr Goodwill [35]

Answer:

The derivative is \frac{dR}{dM}  =  CM - M^2

Step-by-step explanation:

From the question we are told that

The equation representing the reaction is R = M^2 (\frac{C}{2} - \frac{M}{3}  )

Generally this equation can be represented as

R  =  \frac{C M^2}{2}  - \frac{M^3}{3}

Generally \frac{dR}{dM} as a function of M is mathematically represented as

\frac{dR}{dM}  =  2 * \frac{C M^{2 - 1 }}{2}  +  3 * \frac{M^{3-1}}{3}

=> \frac{dR}{dM}  =  CM - M^2

8 0
4 years ago
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