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qaws [65]
2 years ago
9

PLEASE HELP!!!

Chemistry
1 answer:
MA_775_DIABLO [31]2 years ago
6 0

Answer:

424 °C

Explanation:

If all other variables are held constant, the missing temperature can be found using the Charles' Law equation:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can plug the given values into the equation and simplify to find the final temperature.

V₁ = 435 mL                    V₂ = 842 mL

T₁ = 219 °C                       T₂ = ? °C

V₁ / T₁ = V₂ / T₂                                          <----- Charles' Law

435 mL / 219 °C = 842 mL / T₂                <----- Insert values

1.9863 = 842 mL / T₂                               <----- Simplify left side

(1.9863) x T₂ = 842 mL                             <----- Multiply both sides by T₂

T₂ = 424 °C                                              <----- Divide both sides by 1.9863

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Cu2(s)+O2(g)=Cu2O(g)+SO2(g)<br><br>please help urgent will give brainiest​
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Answer:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

Explanation:

2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2

3 0
3 years ago
A sample of xenon gas collected at a pressure of 948 mm Hg and a temperature of 283 K has a mass of 128 grams. What is the volum
disa [49]

Answer:

V = 1.84 × 10³ L

Explanation:

You need to use the Ideal Gas Law and solve for volume.

PV = nRT

V = nRT/P

First, you need to convert the pressure to atm.

1 atm = 760 mm Hg

948/760 = 1.247 atm

Next, convert grams of xenon to moles.  The molar mass is 131.293 g/mol.

128/131.293 = 0.975 mol

You now have all of the values needed.

P = 1.247 atm

n = 0.975 mol

R = 8.314 J/mol*K

T = 283 K

Plug the values in and solve.

V = nRT/P

V = (0.975 × 8.314 × 283)/1.247

V = 1.84 × 10³ L

The volume of the sample will be 1.84 × 10³ L.

7 0
3 years ago
A chemist adds 405.0mL of a 0.79M sodium carbonate solution to a reaction flask. Calculate the millimoles of sodium carbonate th
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Answer:

320 mmol

Explanation:

405.0 mL * 1L/1000 mL = 0.4050 L

0.79 M = 0.79 mol/L

0.79 mol/L * 0.4050 L=0.32 mol

0.32 mol * 10^3 mmol/1 mol = 320 mmol

4 0
4 years ago
A balloon filled with air has a volume of 0.500 L at 25.0 ºC and an internal pressure of 1.20 atm. What will the volume of the b
Alex_Xolod [135]

Answer:

0.441 L

Explanation:

At constant pressure, Using Charle's law  :-

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 0.500 L

V₂ = ?

T₁ = 25.0 °C

T₂ = -10.0 °C  

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (25 + 273.15) K = 298.15 K  

T₂ = (-10 + 273.15) K = 263.15 K  

Using above equation as:

\frac{0.500}{298.15}=\frac{V_2}{263.15}

V_2=\frac{0.500\cdot \:263.15}{298.15}

<u>New volume = 0.441 L</u>

4 0
3 years ago
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