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yan [13]
1 year ago
5

I know only one answer whats the other one help me image-

Mathematics
1 answer:
miv72 [106K]1 year ago
7 0

Answer:

A. 4(4a + 18)

B. 8(2a + 9)

Step-by-step explanation:

<u><em>We know that</em></u> :

16a = 4×4×a

72 = 4×18

Then

16a + 72 = 4×(4a) + 4×(18)

              = 4 × (4a + 18)

On the other hand,

16a = 8×2×a

72 = 8×9

Then

16a + 72 = 8×(2a) + 8×(9)

              = 8 × (2a + 9)

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If five numbers are selected at random from the set {1,2,3,...,20}, what is the probability that their minimum is larger than 5?
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Answer:

the probability that their minimum is larger than 5 is 0.2373

Step-by-step explanation:

For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.

So the number of possibilities to select 5 numbers from 20 is:

<u>20                </u> * <u>      20         </u>*  <u>        20     </u> *<u>        20         </u>* <u>       20 </u>

First number  2nd number   3rd number  4th number   5th number

Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are  20^{5} ways to select 5 numbers.

Then the number of possibilities in which their minimum number is larger than 5 is calculate as:

<u>15                </u> * <u>      15         </u>*  <u>           15     </u> *<u>        15          </u>* <u>       15 </u>

First number  2nd number   3rd number  4th number   5th number

This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are  15^{5}

So the probability P can be calculate as:

P=\frac{15^{5} }{20^{5} } \\P=0.2373

Then the probability that their minimum is larger than 5 is 0.2373

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3 years ago
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