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const2013 [10]
3 years ago
13

If an unknown element displays many extremely strong metallic properties, where is it most likely to be located on the periodic

table?
far right
along the "stair step"
middle
far left
Chemistry
2 answers:
Rudiy273 years ago
8 0

Answer : Option D) far left.

Explanation : If an unknown element displays many extremely strong metallic properties, where is it most likely to be located on the far left of the modern periodic table.

In the modern periodic table, the metallic character of the elements decreases across the periods in the periodic table from left to right. This occurs because the elemental atoms more readily accept electrons to fill their valence shell than losing them to remove the unfilled shell. Also, the metallic character increases down the groups in the periodic table. So, it is clear that the elements found on the far left are having high metallic properties in them.

zheka24 [161]3 years ago
7 0
Metals of such ability are in group 1 and 2 so it is placed on the far left.
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If volumes are additive and 253 mL of 0.19 M potassium bromide is mixed with 441 mL of a potassium dichromate solution to give a
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Answer:

The concentration of the Potassium Dichromate solution is 0.611 M

Explanation:

First of all, we need to understand that in the final solution we'll have potassium ions coming from KBr and also K2Cr2O7, so we state the dissociation equations of both compounds:

KBr (aq) → K+ (aq) + Br- (aq)

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According to these balanced equations when 1 mole of KBr dissociates, it generates 1 mole of potassium ions. Following the same thought, when 1 mole of K2Cr2O7 dissociates, we obtain 2 moles of potassium ions instead.

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0.19 M KBr: this means that we have 0.19 moles of KBr in 1000 mL solution. So:

1000 mL solution ----- 0.19 moles of KBr

253 mL solution ----- x = 0.04807 moles of KBr

As we said before, 1 mole of KBr will contribute with 1 mole of K+, so at the moment we have 0.04807 moles of K+.

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1000 mL solution ----- 0.846 moles K+

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0.587124 final K+ moles - 0.04807 K+ moles from KBr = 0.539054 K+ moles from K2Cr2O7

If we go back and take a look a the chemical reactions, we can see that 1 mole of K2Cr2O7 dissociates into 2 moles of K+ ions, so:

2 K+ moles ----- 1 K2Cr2O7 mole

0.539054 K+ moles ---- x = 0.269527 K2Cr2O7 moles

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441 mL ----- 0.269527 K2Cr2O7 moles

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