1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
malfutka [58]
3 years ago
12

Compare and contrast the concepts of average mass and relative mass. Which one is more accurate, and why? Why is the one you did

not choose inaccurate?
Chemistry
2 answers:
Nina [5.8K]3 years ago
6 0
A very ded dhdhdhjsoaocheoahfea
Brut [27]3 years ago
4 0

Answer:

Relative and average atomic mass both describe properties of an element related to its different isotopes.

Explanation:However, relative atomic mass is a standardized number that's assumed to be correct under most circumstances, while average atomic mass is only true for a specific sample.

You might be interested in
Which one of the following is not equal to 100 meters
Katena32 [7]
Where is the link can’t do any work without it
7 0
3 years ago
Which of the following is true about the coefficients in a balanced chemical equation?
aliina [53]

Answer:

Where is the chemical equations?

6 0
3 years ago
Read 2 more answers
Bas +<br> PtF2 →<br> BaF2 +<br> Pts<br> Need to balance it
Basile [38]

it is already balanced

REACTANTS

Barium sulfide (BaS) + platinum (Ii) fluoride

PRODUCT

Barium fluoride (BaF2) + Cooperite (PtS)

Hope this answer helps you dear! take care

5 0
2 years ago
What mass of butane in grams is necessary to produce 1.5×103 kJ1.5×103 kJ of heat? What mass of CO2CO2 is produced? Assume the r
saul85 [17]

32.8 g of Butane is required and 99.3 g of CO₂ is produced

<u>Explanation:</u>

The above mentioned reaction can be written as,

C₄H₁₀(g) + 13 O₂(g) → 4CO₂(g) + 5 H₂O(g)     where ΔH (rxn)= -2658 kJ

It is given that 1.5 × 10³ kJ of energy is produced, the original reaction says that 2658 kJ of heat is produced, which means that less than one mole of butane is used in the reaction.

That is

$\frac{1500}{2658}=0.564 \text { moles }    of butane reacted

Now this moles is converted into mass by multiplying it with its molar mass  = 0.564 mol × 58.122 g / mol

                     = 32.8 g of butane.

Mass of CO₂ produced = 0.564 ×44.01 g /mol × 4 mol

                                        = 99.3 g of CO₂

Thus 32.8 g of Butane is required and 99.3 g of CO₂ is produced

7 0
3 years ago
according to the balanced chemical equation below,how many grams of h20 are produced if 3.98g of co2 were produced. 2C18H18 + 25
telo118 [61]

Answer:

Primero debes usar los gramos de co2 y luego buscar su peso molecular, luego de eso usar la relación de moles entre CO2 y H2O y por último buscar el pm del H2O pata ver cuantos gramos de produce.

Explanation:

3 0
3 years ago
Other questions:
  • Which drug treats heartburn by neutralizing the acidity of the stomach by combining with hydrochloric acid (hcl) and increasing
    15·1 answer
  • A gas contains 75.0 wt% methane, 10.0% ethane, 5.0% ethylene, and the balance water. (a) Calculate the molar composition of this
    8·1 answer
  • What is the chemical formula for the compound formed between rubidium and iodine?
    14·1 answer
  • Calcium ions, barium ions, and magnesium ions all have two positive charges. What could explain the differences in the way each
    14·2 answers
  • A chemist weighed out 20.7 g of sodium . Calculate the number of moles of sodium she weighed out
    7·1 answer
  • A sample of sulfur hexafluoride gas occupies a volume of 9.10 L at 198ÁC. Assuming that the pressure remains constant, what temp
    6·2 answers
  • How many moles of C6H1206 are consumed if 6 moles of O2 are consumed?​
    15·2 answers
  • An atom has 13 protons, 14 neutrons, and 10 electrons. What element is this atom? How did you determine which element it was?
    14·2 answers
  • Need a little help with science please
    6·2 answers
  • CF4 + Br2 CBr4 + F2
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!