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malfutka [58]
3 years ago
12

Compare and contrast the concepts of average mass and relative mass. Which one is more accurate, and why? Why is the one you did

not choose inaccurate?
Chemistry
2 answers:
Nina [5.8K]3 years ago
6 0
A very ded dhdhdhjsoaocheoahfea
Brut [27]3 years ago
4 0

Answer:

Relative and average atomic mass both describe properties of an element related to its different isotopes.

Explanation:However, relative atomic mass is a standardized number that's assumed to be correct under most circumstances, while average atomic mass is only true for a specific sample.

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What is the heat in joules required to convert 75.0 grams of water into steam if the ^Hvap of water is 2257j/g?
nikitadnepr [17]

169 000 J. It takes 169 000 J to convert 75.0 g of water to steam.

<em>q</em> = <em>m</em>Δ<em>H</em>vap = 75.0 g x (2257 J/1 g) = 169 000 J

7 0
3 years ago
Use the changes in oxidation numbers to identify which atom is oxidized, reduced, the oxidizing agent, and the reducing agent. 5
Vinil7 [7]

Answer:

Reaction A:

  • Hydrogen atoms in H₂ are oxidized.
  • Oxygen atoms in O₂ are reduced.
  • Hydrogen gas H₂ is the reducing agent.
  • Oxygen gas O₂ is the oxidizing agent.

Reaction B:

  • Oxygen atoms in KNO₃ are oxidized.
  • Nitrogen atoms in KNO₃ are reduced.
  • Potassium nitrate (V) KNO₃ is both the oxidizing agent and the reducing agent.

Explanation:

  • When an atom is oxidized, its oxidation number increases.
  • When an atom is reduced, its oxidation number decreases.
  • The oxidizing agent contains atoms that are reduced.
  • The reducing agent contains atoms that are oxidized.

Here are some common rules for assigning oxidation states.

  • Oxidation states on all atoms in a neutral compound shall add up to 0.
  • The average oxidation state on an atom is zero if the compound contains only atoms of that element. (E.g., the oxidation state on O in O₂ is zero.)
  • The oxidation state on oxygen atoms in compounds is typically -2. (Exceptions: oxygen bonded to fluorine, and peroxides.)
  • The oxidation state on group one metals (Li, Na, K) in compounds is typically +1.
  • The oxidation state on group two metals (Mg, Ca, Ba) in compounds is typically +2.
  • The oxidation state on H in compounds is typically +1. (Exceptions: metal hydrides where the oxidation state on H can be -1.)

For this question, only the rule about neutral compounds, oxygen, and group one metals (K in this case) are needed.

<h3>Reaction B</h3>

Oxidation states in KNO₃:

  • K is a group one metal. The oxidation state on K in the compound KNO₃ shall be +1.
  • The oxidation state on N tend to vary a lot, from -3 all the way to +5. Leave that as x for now.
  • There's no fluorine in KNO₃. The ion NO₃⁻ stands for nitrate. There's no peroxide in that ion. The oxidation state on O in this compound shall be -2.
  • Let the oxidation state on N be x. The oxidation state of all five atoms in the formula KNO₃ shall add up to zero. 1\times (+1) + 1 \times (x) + {\bf 3} \times (-2) = 0\\x = +5. As a result, the oxidation state on N in KNO₃ will be +5.

Similarly, for KNO₂:

  • The oxidation state on the group one metal K in KNO₂ will still be +1.
  • Let the oxidation state on N be y.
  • There's no peroxide in the nitrite ion, NO₂⁻, either. The oxidation state on O in KNO₂ will still be -2.
  • The oxidation state on all atoms in this formula shall add up to 0. Solve for the oxidation state on N: 1\times (+1) + 1 \times (y) + {\bf 2}\times (-2) = 0\\y = +3. The oxidation state on N in KNO₂ will be +3.

Oxygen is the only element in O₂. As a result,

  • The oxidation state on O in O₂ will be 0.

\rm\stackrel{+1}{K}\stackrel{\bf +5}{N}\stackrel{\bf -2}{O}_3 \to \stackrel{+1}{K}\stackrel{\bf+3}{N}\stackrel{\bf -2}{O}_2 + \stackrel{\bf 0}{O}_2.

The oxidation state on two oxygen atoms in KNO₃ increases from -2 to 0. These oxygen atoms are oxidized. KNO₃ is also the reducing agent.

The oxidation state on the nitrogen atom in KNO₃ decreases from +5 to +3. That nitrogen atom is reduced. As a result, KNO₃ is also the oxidizing agent.

<h3>Reaction A</h3>

Apply these steps to reaction A.

H₂:

  • Oxidation state on H: 0.

O₂:

  • Oxidation state on O: 0.

H₂O:

  • Oxidation state on H: +1.
  • Oxidation state on O: -2.
  • Double check: {\bf 2} \times (+1) + (-2) = 0.

\rm \stackrel{}{2}\; \stackrel{\bf 0}{H}_2 + \stackrel{\bf 0}{O}_2\stackrel{}{\to} \stackrel{}{2}\;\stackrel{\bf +1}{H}_2\stackrel{\bf -2}{O}.

The oxidation state on oxygen atoms decreases from 0 to -2. Those oxygen atoms are reduced. O₂ is thus the oxidizing agent.

The oxidation state on hydrogen atoms increases from 0 to +1. Those hydrogen atoms are oxidized. H₂ is thus the reducing agent.

4 0
3 years ago
How many grams are there in 1.18 X 1026 atoms of iridium?
stealth61 [152]
You want to divide by avagadros number (6.22 x 10^23). This will cancel the atoms unit and give moles, moles of Iridium. Now you want to calculate the atomic mass of Iridium which is in units of grams per mole. Multiply these two numbers and the moles will cancel giving you grams.

Setting up a dimension analysis type of thing helps tremendously. See what you have to cancel in order to get what you want. We canceled the atoms, then we canceled the moles, and then we got grams.
4 0
3 years ago
DNA bases are attached to _____.
melomori [17]

Answer:

both sugar and phosphate molecules

5 0
3 years ago
Read 2 more answers
True or False: If you have 2 moles of water and 2 moles of carbon, you have the same number of molecules.
nikklg [1K]
True.
moles x avagadro number = molecules
8 0
3 years ago
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