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Misha Larkins [42]
1 year ago
7

3x/2y=11 x+y/2=7 igualacion Alguien me puede ayudar

Mathematics
1 answer:
bearhunter [10]1 year ago
3 0

La solución del sistema de ecuaciones es igual a (x, y) = (308/47, 42/47).

<h3>¿Cómo resolver un sistema de ecuaciones linear por igualación?</h3>

Los sistemas de ecuaciones basadas en entidades algebraicas se resuelven mediante procedimientos algebraicos. Grosso modo, el método de resolución por igualación consiste en despejar una variable en dos ecuaciones del sistema para eliminarla y reducir el número de ecuaciones <em>lineales</em> y el número de variables.

A continuación, presentamos una aplicación del método de eliminación:

\frac{3\cdot x}{2\cdot y} = 11

x = \frac{22\cdot y}{3}

x + \frac{y}{2} = 7

x = 7 - \frac{y}{2}

\frac{22\cdot y}{3} = 7 - \frac{y}{2}

\frac{47\cdot y}{6} = 7

y = 42/47

x = 7 - \frac{y}{2}

x = 308/47

La solución del sistema de ecuaciones es igual a (x, y) = (308/47, 42/47).

Para aprender más sobre los sistemas de ecuaciones: brainly.com/question/15811265

#SPJ1

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Answer:

Probability of landing  cream cheese side up 3 times is tex]\frac{1}{4}[/tex]

Step-by-step explanation:

The probability of getting cheese side up is one half (\frac{1}{2}.

And this probability does not depend on the result of the last time you dropped it or the result before that.

So every time you drop a piece of toast the probability of getting cheese side up is one half (\frac{1}{2}.

Charlie has already dropped it once (1st time) and it landed on cream cheese side up. So probability for this is 1 because it has already happened.

Next time (2nd time) he drops, the probability of landing cream cheese side up is \frac{1}{2}

When he drops the piece of toast again (3rd time) the probability of landing cheese side up is again \frac{1}{2}.

So the probability of landing  cream cheese side up 3 times is,

1*\frac{1}{2} *\frac{1}{2}

=\frac{1}{4}


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