Answer:
A. Shear stresses are maximum at the neutral axis and normal stresses are maximum furthest from the neutral axis.
Explanation:
Normal stress :
Normal stress is defined as the stress or the restoring force that occurs on the plane when an external axial load is applied on it. For a beam the normal stress is maximum at the point furthest from the neutral axis and is zero at the neutral axis of the beam.
Shear stress :
Shear stress is a stress which occurs when the force acts on the surface of the member in a parallel direction. It changes the shape of the member. For a beam, the shear stress is maximum at the neutral axis.
Answer:
as
- Mass of sun > Mass of earth
Therefore, the sun will exert more gravitational force on earth.
Explanation:
While comparing the gravitational force exerted by two objects, we need to observe which object has a greater mass.
- The object with the greater mass exerts a more gravitational force on the other object.
We know that mass of the sun is about 1.99 x 10³⁰ kg, and the earth's mass is only 6.0 x 10²⁴.
as
- Mass of sun > Mass of earth
Therefore, the sun will exert more gravitational force on earth.
Answer:
The answer to your question is distance between these electrons
= 1.386 x 10⁻¹⁴ m
Explanation:
Data
Force = F = 1.2 N
distance = d = ?
charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C
K = 8.987 x 10⁹ Nm²/C²
Formula
-To solve this problem use the Coulomb's equation
F = kq₁q₂ / r²
-Solve for r²
r² = kq₁q₂ / F
-Substitution
r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2
- Simplification
r² = 2.306 x 10⁻²⁸ / 1.2
r² = 1.922 x 10⁻²⁸
-Result
r = 1.386 x 10⁻¹⁴ m
Answer:
0.705 m/s²
Explanation:
a) The sprinter accelerates uniformly from rest and reaches a top speed of 35 km/h at the 67-m mark.
Using newton's law of motion:
v² = u² + 2as
v = final velocity = 35 km/h = 9.72 m/s, u = initial velocity = 0 km/h, s = distance = 67 m
9.72² = 0² + 2a(67)
134a = 94.484
a = 0.705 m/s²
b) The sprinter maintains this speed of 35 km/h for the next 88 meters. Therefore:
v = 35 km/h = 9.72 m/s, u = 35 km/h = 9.72 m/s, s = 88 m
v² = u² + 2as
9.72² = 9.72² + 2a(88)
176a = 9.72² - 9.72²
a = 0
c) During the last distance, the speed slows down from 35 km/h to 32 km/h.
u = 35 km/h = 9.72 m/s, v = 32 km/h = 8.89 m/s, s = 200 - (67 + 88) = 45 m
v² = u² + 2as
8.89² = 9.72² + 2a(45)
90a = 8.89² - 9.72²
90a = -15.4463
a = -0.1716 m/s²
The maximum acceleration is 0.705 m/s² which is from 0 to 67 m mark.
