Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19 C and Coulomb's constant is 8.987 × 109 N · m2/C2. Answer in units of m.
1 answer:
Answer:
The answer to your question is distance between these electrons
= 1.386 x 10⁻¹⁴ m
Explanation:
Data
Force = F = 1.2 N
distance = d = ?
charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C
K = 8.987 x 10⁹ Nm²/C²
Formula
-To solve this problem use the Coulomb's equation
F = kq₁q₂ / r²
-Solve for r²
r² = kq₁q₂ / F
-Substitution
r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2
- Simplification
r² = 2.306 x 10⁻²⁸ / 1.2
r² = 1.922 x 10⁻²⁸
-Result
r = 1.386 x 10⁻¹⁴ m
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