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vaieri [72.5K]
2 years ago
11

How long will it take for a car at rest to accelerate at 7m/s^2 to a speed of 45 m/s

Physics
1 answer:
Gennadij [26K]2 years ago
8 0
Speed/acceleration = time
45/7
6.4
You have to round the decimal to 6.4
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The answer is "heat transfer."
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A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.320 m2. at
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5. A ball rolls off a 1.5 m tall horizontal table and lands on the floor 0.70 m away.
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Take the starting position of the ball 1.5 m above the floor to be the origin. Then at time t, the ball's horizontal and vertical positions from the origin are

x = v₀ t

y = -1/2 gt²

where v₀ is the initial speed with which it rolls off the edge and g = 9.8 m/s².

A. The floor is 1.5 m below the origin, so we solve for t when y = -1.5 m :

-1.5 m = -1/2 gt²

⇒   t² = (3.0 m)/g

⇒   t = √((3.0 m)/g) ≈ 0.55 s

B. It would take the same amount of time.

C. The ball travels a horizontal distance of 0.70 m before reaching the floor, so we solve for v₀ with t = 0.55 s :

0.70 m = v₀ (0.55 s)

⇒   v₀ = (0.70 m) / (0.55 s) ≈ 1.3 m/s

D. At time t, the ball has horizontal and vertical velocity components

v[x] = 1.3 m/s

v[y] = -gt

so the horizontal component of the ball's final velocity vector is the same as the initial one, 1.3 m/s.

E. The vertical component of velocity would be

v[y] = -g (0.55 s) ≈ -5.4 m/s

F. The magnitude of the final velocity would be

√((1.3 m/s)² + (-5.4 m/s)²) ≈ 5.6 m/s

G. The final velocity vector makes an angle θ with the horizontal such that

tan(θ) = (-5.4 m/s) / (1.3 m/s)

⇒   θ = arctan(-5.4/1.3) ≈ -77°

i.e. approximately 77° below the horizontal.

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2 years ago
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