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3 years ago

What is the gravitational force between Earth and a 10 kg object on Earth’s surface?

Physics

1 answer:

4vir4ik [10]3 years ago

6 0

Answer:

The force between the Earth and the object is, F = 9.61 x 10⁻¹² N

Explanation:

Given data,

The mass of the Earth, M = 5.9 x 10²⁴ kg

The mass of the object, m = 10 kg

The gravitational force between the earth and the object is given by the formula,

F = G Mm/R²

Substituting the given values in the above equation,

F = 6.673 x 10⁻¹¹ x 5.9 x 10²⁴ x 10 / 6.4 x 10⁶

= 9.61 x 10⁻¹² N

Hence, the force between the Earth and the object is, F = 9.61 x 10⁻¹² N

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A rock is thrown at an angle of 60∘ to the ground. If the rock lands 25m away, what was the initial speed of the rock? (Assume a

Zinaida [17]

Answer:

$v_0 = 16.82\ m/s$

Explanation:

given,

angle at which rock is thrown = 60°

rock lands at distance,d = 25 m

initial speed of rock, = ?

In horizontal direction

distance = speed x time

d = v₀ cos 60° t

25 = v₀ cos 60° t............(1)

now,

in vertical direction

displacement in vertical direction is zero

using equation of motion

$s = ut +\dfrac{1}{2}gt^2$

$0 =v_0 sin 60^0 t - 4.9 t^2$

$v_o sin 60^0 = 4.9 t$

$t = \dfrac{v_0 sin 60^0}{4.9}$

putting the value of t in equation (1)

$25 = v_0 cos 60^0\times \dfrac{v_0 sin 60^0}{4.9}$

$25 =\dfrac{v_0^2cos 60^0 sin 60^0}{4.9}$ v

$v_0^2 = 282.90$

$v_0 = 16.82\ m/s$

Hence, the initial speed of the rock is equal to 16.82 m/s

4 0

3 years ago

The weight of a girl with the mass of 40.0kg is ?

Allushta [10]

Answer:

392 Newtons

Explanation:

In order to find the weight, you have to multiply the mass by the gravitation constant (9.8), which gives us 40.0 * 9.8 = 392 Newtons.

4 0

3 years ago

a fire woman dropped a person onto the safety net. right before the person hit the net he had a velocity of 11.2m/s and 1800j of

Ludmilka [50]

Answer: 28.699

Explanation:

KE=1/2(mv²)

1800=1/2m (125.44)

14.349=2m

m=28.699

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3 years ago

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What is the equation linking pressure difference, depth, density and g

Leokris [45]

Pressure difference = depth x density x gravity

7 0

3 years ago

A space vehicle is traveling at 2980 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The

Strike441 [17]

Answer:

3054.4 km/h

Explanation:

Using the conservation of momentum

momentum before separation = 5M × 2980 Km/h where M represent the mass of the module while 4 M represent the mass of the motor

initial momentum = 14900 M km/h

let v be the new speed of the motor so that the

new momentum = 4Mv and the new momentum of the module = M ( v + 94 km/h )

total momentum = 4Mv + Mv + 93 M = 5 Mv + 93M

initial momentum = final momentum

14900 M km/h = 5 Mv + 93M

14900 km/h = 5v + 93

14900 - 93 = 5v

v = 2961.4 km/h

the speed of the module = 2961.4 + 93 = 3054.4 km/h

8 0

3 years ago