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Anon25 [30]
3 years ago
9

What is the gravitational force between Earth and a 10 kg object on Earth’s surface?

Physics
1 answer:
4vir4ik [10]3 years ago
6 0

Answer:

The force between the Earth and the object is, F = 9.61 x 10⁻¹² N

Explanation:

Given data,

The mass of the Earth, M = 5.9 x 10²⁴ kg

The mass of the object, m = 10 kg

The gravitational force between the earth and the object is given by the formula,

                         F = G Mm/R²

Substituting the given values in the above equation,

                         F = 6.673 x 10⁻¹¹ x 5.9 x 10²⁴ x 10 / 6.4 x 10⁶

                            =  9.61 x 10⁻¹² N

Hence, the force between the Earth and the object is, F = 9.61 x 10⁻¹² N

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Answer:

    K = m g (A - A2)

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In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential

         Em = U₀ = m g A

For when the system is at an ele

Elongation A2 less than A, energy has two parts

        Em = K + U₂

       K = Em –U₂

We substitute

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    K = m g (A - A2)

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What ecosystem do killer whales and seals belong to?
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3 years ago
the wattage ratting of a light bulb is the power it sonsumers when it is connected accross a 120 V potential difference what is
igor_vitrenko [27]

Answer:

240 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of current in an electric field. The S.I unit of resistance is ohms (Ω).

The expression for resistance power and voltage is give as,

P = V²/R.......................... Equation 1

Where P = Power, V = Voltage, R = Resistance

Making R the subject of the equation,

R = V²/P.................... Equation 2

Given: V = 120 V, P = 60 W.

Substitute into equation 2

R = 120²/60

R = 240 Ω

Hence the resistance of the bulb = 240 Ω

8 0
3 years ago
A long solenoid of radius 3 cm has 1100 turns per meter. If the solenoid carries a current of 1.5 A, then calculate the magnetic
Arada [10]

Answer:

The magnetic field at the center of the solenoid is 2.1  × 10⁻³ T

Explanation:

The magnetic field B at the center of the solenoid is given by

B = μ₀ni where μ₀ = permeability of free space = 4π × 10⁻⁷H/m, n = number of turns per unit length of the solenoid = 1100 turns per meter and i = current in the solenoid = 1.5 A.

So B = μ₀ni

= 4π × 10⁻⁷H/m × 1100 × 1.5 A

= 4π × 10⁻⁷H/m × 1650 A-turns/m

= 20734.5 × 10⁻⁷T  

= 2.07345 × 10⁻³ T

≅ 2.1  × 10⁻³ T

So the magnetic field at the center of the solenoid is 2.1  × 10⁻³ T

3 0
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