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2 years ago

A flux used for welding, brazing, or soldering prevents the formation of, dissolves, or helps remove?

Engineering

1 answer:

OverLord2011 [107]2 years ago

8 0

Answer:

Helps to remove Oxides formed during brazing.

Explanation:

Flux is needed to dissolve and remove oxides that may form during brazing. Prevent or inhibit the formation of oxide during the brazing process

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Parity Detect of Three Inputs 20 pts. (EVEN) a) Draw a function table showing the three data lines and the output function F. 4

DIA [1.3K]

Answer:

See attached picture.

Explanation:

4 0

3 years ago

Rewrite the following nested if-else statement as a switch statement that accomplishes exactly the same thing. Assume that num i

seropon [69]

Answer:

Answer explained below

Explanation:

The following is the nested if-else statement:

% if-based statement

if num < -2 || num > 4

f1(num)

else

if num <=2

if num >= 0

f2(num)

else

f3(num)

end

else

f4(num)

end

<u>NOTE:</u> the num is an integer variable that has been initialized and that there are functions f1, f2, f3 and f4.

The nested if-else statement can be replaced by switch statement as shown below:

switch num

case(0, 1, 2)

f2(num)

case(-2, -1)

f3(num)

case(3, 4)

f4(num)

otherwise

f1(num)

In this case, the switch based code is easier to write and understand because the cases are single valued or a few discrete values (not ranges of values)

8 0

3 years ago

De acuerdo con el tabulador de puestos de una compañía, los salarios mensuales que obtienen los trabajadores son los que se mues

inessss [21]

Sorry don’t understand

8 0

3 years ago

In a shear box test on sand a shearing force of 800 psf was applied with normal stress of 1750 psf. Find the major and minor pri

ryzh [129]

Answer:

The major and minor stresses are as 2060.59 psf, -310.59 psf and 1185.59 psf.

Explanation:

The major and minor principal stresses are given as follows:

$\sigma_{max}=\dfrac{\sigma_x+\sigma_y}{2}+\sqrt{\left(\dfrac{\sigma_x-\sigma_y}{2}\right)^2+\tau_{xy}^2}$

$\sigma_{min}=\dfrac{\sigma_x+\sigma_y}{2}-\sqrt{\left(\dfrac{\sigma_x-\sigma_y}{2}\right)^2+\tau_{xy}^2}$

Here

$\sigma_x$ is the normal stress which is 1750 psf
$\sigma_y$ is 0
$\tau_{xy}$ is the shear stress which is 800 psf

So the formula becomes

$\sigma_{max}=\dfrac{\sigma_x+\sigma_y}{2}+\sqrt{\left(\dfrac{\sigma_x-\sigma_y}{2}\right)^2+\tau_{xy}^2}\\\sigma_{max}=\dfrac{1750+0}{2}+\sqrt{\left(\dfrac{1750-0}{2}\right)^2+(800)^2}\\\sigma_{max}=875+\sqrt{\left(875)^2+(800)^2} \\\sigma_{max}=875+\sqrt{765625+640000}\\\sigma_{max}=875+1185.59\\\sigma_{max}=2060.59 \text{psf}$

Similarly, the minimum normal stress is given as

$\sigma_{min}=\dfrac{\sigma_x+\sigma_y}{2}-\sqrt{\left(\dfrac{\sigma_x-\sigma_y}{2}\right)^2+\tau_{xy}^2}\\\sigma_{min}=\dfrac{1700+0}{2}-\sqrt{\left(\dfrac{1700-0}{2}\right)^2+(800)^2}\\\sigma_{min}=875-\sqrt{(875)^2+(800)^2}\\\sigma_{min}=875-\sqrt{765625+640000}\\\sigma_{min}=875-1185.59\\\sigma_{min}=-310.59 \text{ psf}$

The maximum shear stress is given as

$\tau_{max}=\dfrac{\sigma_{max}-\sigma_{min}}{2}\\\tau_{max}=\dfrac{2060.59-(-310.59)}{2}\\\tau_{max}=\dfrac{2371.18}{2}\\\tau_{max}=1185.59 \text{psf}$

5 0

3 years ago

Calculate the kinetic energy in kJ of an automobile (3,000 lb) travelling at 60 miles per hour.

AlladinOne [14]

Answer:

K = 18.26 KJ

Explanation:

See it in the pic.

4 0

3 years ago