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babunello [35]
3 years ago
12

Four subjects civil engineers need to study​

Engineering
1 answer:
stira [4]3 years ago
4 0

Answer:

A civil engineering degree program applies mathematics and physical science to solve specific, real-world problems in commerce and industry. A strong civil engineering program typically emphasizes the practical use of geometry, trigonometry, and calculus in conjunction with physics, material science, and chemistry.

Explanation:

Hope this helps!! Please consider marking brainliest! Have a good one!!

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Assume the availability of an existing class, ICalculator, that models an integer arithmetic calculator and contains: an instanc
shtirl [24]

We connect with computers through coding, often known as computer programming.

<h3>How to code?</h3>
  • We connect with computers through coding, often understood as computer programming.
  • Coding exists similar to writing a set of instructions because it instructs a machine what to do.
  • You can instruct computers what to do or how to behave much more quickly by learning to write code.

class ICalculator {

int currentValue;

int add(int value) {

this.currentValue = currentValue + value;

return currentValue;

}

int sub(int value) {

this.currentValue = currentValue - value;

return currentValue;

}

int mul(int value) {

this.currentValue = currentValue * value;

return currentValue;

}

int div(int value) {

this.currentValue = currentValue / value;

return currentValue;

}

}

public class ICalculator2 extends ICalculator {

int negate() {

if (currentValue != 0)

this.currentValue = -currentValue;

return currentValue;

}

public static void main(String[] args) {

ICalculator2 ic = new ICalculator2();

ic.currentValue=5;

System.out.println(ic.add(2));

System.out.println(ic.sub(5));

System.out.println(ic.mul(3));

System.out.println(ic.div(3));

System.out.println(ic.negate());

}

}

To learn more about code, refer to

brainly.com/question/22654163

#SPJ4

3 0
1 year ago
The Cv factor for a valve is 48. Compute the head loss when 30 GPM of water passes through the valve.
dlinn [17]

Answer:

The head loss in Psi is 0.390625 psi.

Explanation:

Fluid looses energy in the form of head loss. Fluid looses energy in the form of head loss when passes through the valve as well.

Given:

Factor cv is 48.

Flow rate of water is 30 GPM.

GPM means gallon per minute.

Calculation:

Step1

Expression for head loss for the water is given as follows:

c_{v}=\frac{Q}{\sqrt{h}}

Here, cv is valve coefficient, Q is flow rate in GPM and h is head loss is psi.

Step2

Substitute 48 for cv and 30 for Q in above equation as follows:

48=\frac{30}{\sqrt{h}}

{\sqrt{h}}=0.625

h = 0.390625 psi.

Thus, the head loss in Psi is 0.390625 psi.

 

5 0
3 years ago
A vertical cylinder (Fig. P3.227) has a 61.18-kg piston locked with a pin, trapping 10 L of R-410a at 10◦C with 90% quality insi
Whitepunk [10]

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Write me here and I will give you my phone number - *pofsex.com*

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4 0
3 years ago
Two particles have a mass of 7.8 kg and 11.4 kg , respectively. A. If they are 800 mm apart, determine the force of gravity acti
aleksley [76]

Answer:

A) About 9.273 \times 10^{-9} newtons

B) 76.518 newtons

C) 111.834 newtons

Explanation:

A) F_g=\dfrac{GM_1M_2}{r^2} , where G is the universal gravitational constant, M 1 and 2 are the masses of both objects in kilograms, and r is the radius in meters. Plugging in the given numbers, you get:

F_g=\dfrac{(6.67408 \times 10^{-11})(7.8)(11.4)}{(0.8)^2}\approx 9.273 \times 10^{-9}

B) You can find the weight of each object on Earth because you know the approximate acceleration due to gravity is 9.81m/s^2. Multiplying this by the mass of each object, you get a weight for the first particle of 76.518 newtons.

C) You can do a similar thing to the previous particle and find that its weight is 11.4*9.81=111.834 newtons.

Hope this helps!

3 0
3 years ago
How are the accelerator and brake pedal positioned in relation to each other? A. The brake pedal is to the right of the accelera
Lunna [17]

Answer:B

Explanation:

7 0
3 years ago
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