Consider a cubic block whose sides are 6 cm long and a cylindrical block whose height and diameter are also 6 cm. both blocks ar
e initially at 22°c and are made of granite (k = 2.5 w/m · °c and a = 1.15x 10-6 m^2/s). now both blocks are exposed to hot gases at 550°c in a furnace on all of their surfaces with a heat transfer coefficient of 45 w/m2 · °c. determine the center temperature of each geometry after 10, 20, and 60 minutes.
1 answer:
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Answer:
The dynamic viscosity and kinematic viscosity are lb-s/in2 and
in2/s.
Explanation:
Step1
Given:
Inner diameter is 2.00 in.
Gap between cups is 0.2 in.
Length of the cylinder is 2.5 in.
Rotation of cylinder is 10 rev/min.
Torque is 0.00011 in-lbf.
Density of the fluid is 850 kg/m3 or 0.00095444 slog/in³.
Step2
Calculation:
Tangential force is calculated as follows:
T= Fr
F = 0.00011 lb.
Step3
Tangential velocity is calculated as follows:
V=1.0472 in/s.
Step4
Apply Newton’s law of viscosity for dynamic viscosity as follows:
lb-s/in².
Step5
Kinematic viscosity is calculated as follows:
in2/s.
Thus, the dynamic viscosity and kinematic viscosity are lb-s/in2 and
in2/s.