Electric field strength decreases as the distance from the source increases.
<h3>
How the distance from the charge affects the magnitude of the electric field?</h3>
The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.
So we can conclude that Electric field strength decreases as the distance from the source increases.
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Answer:
my last answer to a question A man's sound is of the lower pitch as compared to the other options. And we know that pitch is directly proportional to the frequency of sound. So, the frequency of man's voice will be the minimum among all the options.
Answer:
P = 251, 3 W
Explanation:
The intensity is defined as the power emitted per unit area
I = P / A
Since sound is distributed in all directions spherical shape, the area of a sphere is
A = 4π r²
let's clear the power and replace
P = I A
P = I (4π r²)
let's calculate
P = 5.00 (4π 2²)
P = 251, 3 W
initial acceleration of rocket is given as
a = 12 m/s^2
h = 26 m
now we can use kinematics to find its speed
now after this it will be under free fall
so now again using kinematics
at maximum height
total height from the ground = 31.8 + 26 = 57.8 m
Part b)
now after reaching highest height it will fall to ground
So in order to find the speed we can use kinematics again
Part c)
first rocket accelerate to reach height 26 meter and speed becomes 24.98 m/s
now we have
after this it will reach to highest point and final speed becomes zero
now from this it will fall back to ground and reach to final speed 33.67 m/s
now we have
so total time is given as
<em>t = 3.44 + 2.55 + 2.1 = 8.1 s</em>
I am fairly certain it's D. Good luck!
