A 0.208 kg particle with an initial velocity of 1.26 m/s is accelerated by a constant force of 0.766 N over a distance of 0.195
1 answer:
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Answer:
(a)
(b)
(c)
(d)
Solution:
As per the question:
Refractive index of medium 1,
Angle of refraction for medium 1,
Angle of refraction for medium 2,
Now,
(a) The expression for the refractive index of medium 2 is given by using Snell's law:
where
= Refractive Index of medium 2
Now,
(b) The refractive index of medium 2 can be calculated by using the expression in part (a) as:
(c) To calculate the velocity of light in medium 1:
We know that:
Thus for medium 1
(d) To calculate the velocity of light in medium 2:
For medium 2: