1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pychu [463]
3 years ago
10

A 0.208 kg particle with an initial velocity of 1.26 m/s is accelerated by a constant force of 0.766 N over a distance of 0.195

m. Use the concept of energy to determine the final velocity of the particle. (It is useful to double-check your answer by also solving the problem using Newton's Laws and the kinematic equations.)
Physics
1 answer:
eduard3 years ago
3 0

Answer:

Explanation:

Initial kinetic energy of particle

= 1/2 m V²

= .5 x .208 x 1.26²

= .165 J

Work done by force = force x displacement

= .766 x .195

= .149 J

This energy will be added up .

Total final kinetic energy

= initial kinetic energy + work done on the particle

= .165 + .149 J

=  .314 J .

You might be interested in
A boat sails south with the help of a wind blowing in the direction S36°E with magnitude 300 lb. Find the work done by the wind
goldfiish [28.3K]

Answer:

The work done by the wind as the boat moves 130 ft is (rounded) W= 31,550 ft-lb.

Explanation:

F= 300 lb < -54º

Fsouth= 300 lb * cos(36º)

Fsouth= 242.7 lb

d= 130 ft

W= F*d

W= 31551 ft-lb

6 0
2 years ago
A 2,000 kg car is parked at the top of a 30 m high hill. what is its potential energy?
Phoenix [80]
The PE for this question will be 588,000 because we take the mass (2,000 kg), multiply it by 9.8 which is Gravitational Acceleration and then multiply that by the height (30 meters)
6 0
3 years ago
Read 2 more answers
A 2100-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 5.00 m before coming into contact w
aliya0001 [1]

Answer:

   f = 878,080 N

Explanation:

mass of pile driver (m) = 2100 kg

distance of pile driver to steel beam (s) = 5 m

depth of steel driven (d) = 12 cm = 0.12 m

acceleration due to gravity (g0 = 9.8 m/s^{2}

calculate the average force exerted on the pile driver by the beam.

  • from work done = force x distance
  • work done = change in potential energy of the pile driver
  • equating the two equations above we have

               force x distance = m x g x (s - d)

              f x 0.12 = 2100 x 9.8 x (5- (-0.12))

              d = - 0.12 because the steel beam went down at we are taking its  

              initial position to be an origin point which is 0

              f = ( 2100 x 9.8 x (5- (-0.12)) ) ÷ 0.12

                   f = 878,080 N

4 0
3 years ago
Harmfful effect of earthquake
Snowcat [4.5K]

Answer:

Death, Destruction, Loss of home

5 0
3 years ago
Read 2 more answers
1) Momenum is
adelina 88 [10]

Answer:

momentum formula = Mass × Velocity

3 0
3 years ago
Other questions:
  • A certain fuel-efficient hybrid car gets gasoline mileage of 55.0 mpg (miles per gallon). (a) If you are driving this car in Eur
    12·1 answer
  • If light moves from left to right along the x-axis, then the electric field line vibrates along what?? :(
    14·1 answer
  • When it is burned, 1 gallon of gasoline produces 1.3Ã108j of energy. 1500 kg car accelerates from rest to 37 m/s in 10 s. the en
    9·1 answer
  • The impedance of an inductor zind is determined to be 147 ohms at 2000 hz and its dc resistance rl is 25 ohms. what would be the
    10·1 answer
  • What is the difference between living, nonliving, and dead
    11·1 answer
  • Which agents of erosion and deposition generally sort sediments by grain size?
    14·1 answer
  • A 3kg book falls from a shelf. If it lands with a speed of 4.8 m/s, from what height did it fall? A. 28.8 m , B. 1.2 m , C. 0.6
    13·1 answer
  • 5 points !!!is potential chemical energy always transformed into kinetic
    5·1 answer
  • Which statement is true of gravity?
    10·1 answer
  • PLEASE HELP ME I AM TIMED!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!