Question

Two stretched copper wires both experience the same stress. The first wire has a radius of 3.9×10-3 m and is subject to a stretching force of 450 N. The radius of the second wire is 5.1×10-3 m. Determine the stretching force acting on the second wire.

Answer 1

The stretching force acting on the second wire, given the data is 588 N

Data obtained from the question

• Radius of fist wire (r₁) = 3.9×10⁻³ m
• Force of first wire (F₁) = 450 N
• Radius of second wire (r₂) = 5.1×10⁻³ m
• Force of second wire (F₂) =?

How to determine the force of the second wire

F₁ / r₁ = F₂ / r₂

450 / 3.9×10⁻³ = F₂ / 5.1×10⁻³

cross multiply

3.9×10⁻³ × F₂ = 450 × 5.1×10⁻³

Divide both side by 3.9×10⁻³

F₂ = (450 × 5.1×10⁻³) / 3.9×10⁻³

F₂ = 588 N

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