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2 years ago

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Un resorte se alarga 5 cm bajo la acción de una fuerza de 39,2 N. ¿Cuál es la constante del resorte? Si ahora la fuerza es 68,6

N. ¿Cuál es el nuevo alargamiento?

1 answer:

Lorico [155]2 years ago

6 0

Answer:

$k=784 N/m$

$\Delta x=8,8 cm$

Explanation:

Usando la ley de Hook tenemos:

$F=k\Delta x$

Solving it for k we have:

$k=\frac{F}{\Delta x}$

$k=\frac{39,2}{0,05}$

$k=784 N/m$

Usando la misma ecuación y sabiendo k tenemos:

$\Delta x=\frac{F}{k}$

$\Delta x=\frac{68,6}{784}$

$\Delta x=8,8 cm$

Espero esto te ayude!

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temperature of mixture, $T_x=40^{\circ}C$

<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>

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$n_w=\frac{m_w}{M_w}$

$n_w=\frac{313.5}{18}$

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$X_w=\frac{n_w}{n_w+n_g}$

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$\therefore P_{sol}=X_w\times P_x$

$\therefore P_{sol}=0.912\times 55.32$

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