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Zolol [24]
2 years ago
10

Un resorte se alarga 5 cm bajo la acción de una fuerza de 39,2 N. ¿Cuál es la constante del resorte? Si ahora la fuerza es 68,6

N. ¿Cuál es el nuevo alargamiento?
Physics
1 answer:
Lorico [155]2 years ago
6 0

Answer:

k=784 N/m

\Delta x=8,8 cm

Explanation:

Usando la ley de Hook tenemos:

F=k\Delta x

Solving it for k we have:

k=\frac{F}{\Delta x}

k=\frac{39,2}{0,05}

k=784 N/m

Usando la misma ecuación y sabiendo k tenemos:

\Delta x=\frac{F}{k}

\Delta x=\frac{68,6}{784}

\Delta x=8,8 cm

Espero esto te ayude!

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You are at a train station, standing next to the train at the front of the first car. The train starts moving with constant acce
Aleksandr [31]

The time needed for the 7th car to pass is 13.2 s

Explanation:

The motion of the train is a uniformly accelerated motion, therefore we can use suvat equations.

We start by analzying the motion of the first car, by using the equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered by the first car in a time t, which corresponds to the length of one car

u = 0 is the initial velocity

a is the acceleration

t = 5.0 s is the time

The equation can be rewritten as

a=\frac{2s}{t^2}=\frac{2L}{(5.0)^2}=0.08L[m/s^2]

where L is the length of one car.

The same equation can be written considering the first 7 cars:

7L = ut+\frac{1}{2}at'^2

where

7L is the distance covered by the 7 cars

t' is the time needed

We still have

u = 0

And the acceleration is constant so it is

a=0.08L

Substituting into the equation, we can find t':

7L = \frac{1}{2}(0.08L)t'^2\\7=0.04t'^2\\t'=\sqrt{\frac{7}{0.04}}=13.2 s

In attachment the graph of the distance covered versus the time taken: since the motion is uniformly accelerated, the relationship between the two variables is quadratical.

Learn more about accelerated motion:

brainly.com/question/9527152

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brainly.com/question/2506873

brainly.com/question/2562700

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8 0
2 years ago
What is the approximate uncertainty in the area of a circle of radius 4.5×10^4 cm? Express your answer using one significant fig
Igoryamba

Answer:

A=6.36\times 10^5\ m^2

Explanation:

It is given that,

Radius of the circle, r=4.5\times 10^4\ cm=4.5\times 10^2\ m

The area of the circle is given by :

A=\pi r^2

A=\pi (4.5\times 10^2\ m)^2

A=636172.51\ m^2

or

A=6.36\times 10^5\ m^2

As there is no uncertainty given in the radius of the circle. So, the area of the circle is 6.36\times 10^5\ m^2. Hence, this is the required solution.

5 0
3 years ago
3
kap26 [50]

The increase in temperature that will result if 225.0 g of copper absorbs 5000 J of heat energy is 57.72°C.

<h3>How to calculate temperature change?</h3>

The temperature change of a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed or released
  • m = mass of substance
  • c = specific heat capacity
  • ∆T = change in temperature

5000 = 225 × 0.385 × ∆T

5000 = 86.63∆T

∆T = 5000/86.63

∆T = 57.72°C

Therefore, the increase in temperature that will result if 225.0 g of copper absorbs 5000 J of heat energy is 57.72°C.

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3 0
1 year ago
Two vectors pointing right starting at the same position. Vector A is on top and longer. Vector B is shorter and below.
Oksana_A [137]

Answer:

The displacements are not equal. While their direction is the same, their length (i.e., distance or magnitude) is not. A is longer than B.

Explanation:

correct on e2020- sample respnse

4 0
3 years ago
Read 2 more answers
A spring has natural length 16 cm. A force of 3 N is required to holdthe spring compressed compressed to 11 cm. Find the amount
alexgriva [62]

Answer:

W = 0.012 J

Explanation:

For this exercise let's use Hooke's law to find the spring constant

         F = K Δx

         K = F / Δx

         K = 3 / (0.16 - 0.11)

         K = 60 N / m

Work is defined by

         W = F. x = F x cos θ

in this case the force and the displacement go in the same direction therefore the angle is zero and the cosine is equal to 1

         W = ∫ F dx        

         W = k ∫ x dx

we integrate

         W = k x² / 2

          W = ½ k x²

let's calculate

         W = ½ 60 (0.19 -0.17)²

         W = 0.012 J

8 0
2 years ago
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