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Tresset [83]
3 years ago
11

In very cold weather, a significant mechanism for heat loss by the human body is energy expended in warming the air taken into t

he lungs with each breath. A) On a cold winter day when the temperature is -19.0 C, what is the amount of heat needed to warm to internal body temperature (37 C ) the 0.470 J (Kg *K) of air exchanged with each breath? Assume that the specific heat capacity of air is 1020 and that 1.0 L of air has a mass of 1.3 g . B) How much heat is lost per hour if the respiration rate is 21.0 breaths per minute?
Physics
1 answer:
Pie3 years ago
7 0

Answer:

A) Q_a=74256\ J

B) Q=93562560\ J

Explanation:

Given:

  • temperature of air, T_a=-19+273=254\ K
  • temperature of lungs, T_l=37+273=310\ K
  • specific Heat exchanged from the lungs , c_l=0.47\ J.kg^{-1}.K^{-1}
  • specific heat of air, c_a=1020\ J.kg^{-1}.K^{-1}
  • mass of 1 L air, m'=1.3\ kg
  • breath rate, b=21\ breath.min^{-1}

A)

Now,

amount of heat needed to warm the air of lungs to the body temperature:

Q_a=m'.c_a.\Delta T

Q_a=1.3\times1020\times (310-254)

Q_a=74256\ J

B)

Amount of heat lost per hour:

<u>No. of breaths per hour:</u>

B=b.60

B=21\times 60

B=1260

<u>Now the total loss of energy in 1 hr.:</u>

Q=Q_a.B

Q=74256\times 1260

Q=93562560\ J

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