Michelaneglo DDDDDDDDDDDDDDDDDDDDDDDDD
Data is inappropriate
here, we need gauge of the wire i.e., diameter of the wire, so that we calculate the resistance by using the formula
R = ρl/A
where R= resistance ; Ω
l = length of wire ; m
A = area of wire ; m²
ρ = resistivity ; Ω-m
But in general ohms law is
V = I R
R = V/I ;
but here we also calculate "R" from length of wire in which the current is flowing.
I hope it is helpful to you.
Answer:
16.33°C
Explanation:
Applying,
Heat lost by copper = heat gained by water
cm(t₁-t₃) = c'm'(t₃-t₂).............. Equation 1
Where c = specific heat capacity of copper, m = mass of copper, c' = specific heat capacity of water, m' = mass of water, t₁ = initial temperature of copper, t₂ = initial temperature of water, t₃ = final equilibrium temperature.
From the question,
Given: m = 50 kg, t₁ = 140°C, m' = 90 L = 90 kg, t₂ = 10°C
Constant: c = 385 J/kg°C, c' = 4200J/kg°C
Substitute these values into equation 1
50(385)(140-t₃) = 90(4200)(t₃-10)
(140-t₃) = 378000(t₃-10)/19250
(140-t₃) = 19.64(t₃-10)
140-t₃ = 19.64t₃-196.6
19.64t₃+t₃ = 196.4+140
20.64t₃ = 336,4
t₃ = 336.4/20.6
t₃ = 16.33°C
Explanation:
period of pendulum = time taken for 1 oscillation = time taken for 1 complete back and forth vibration
q1 ans is given in question its 1.5 sec
q2 ans is 1.5 sec longer than 1 sec period
Answer:
a) 
, b) 
, c) 
Explanation:
a) The turbine is modelled by means of the First Principle of Thermodynamics. Changes in kinetic and potential energy are negligible.
The mass flow rate is:
According to property water tables, specific enthalpies and entropies are:
State 1 - Superheated steam
State 2s - Liquid-Vapor Mixture
The isentropic efficiency is given by the following expression:
The real specific enthalpy at outlet is:
State 2 - Superheated Vapor
The mass flow rate is:
b) The temperature at the turbine exit is:
c) The rate of entropy generation is determined by means of the Second Law of Thermodynamics:
