Liters
Grams
Degrees Celsius
The other answer choices are from the imperial system
Answer:
The force exerted by three charges on the fourth is 
Explanation:
Given:
- The magnitude of three identical charges,

- Length of the edge of the square a=3 cm
- Magnitude of fourth charge ,Q=3 nC
According to coulombs Law the force F between any two charge particles is given by

where r is the radial distance between them.
Since the force acting on the charge particle will be in different directions so according to triangle law of vector addition

did you mean what activities are performed during the cool down?