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Yakvenalex [24]
3 years ago
14

If the wavelength of orange light is 6 · 10-7 m, calculate its frequency. f = _______ Hz

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

<u>Answer:</u>

Frequency of orange light = 5 \times 10^{14} Hz

<u>Explanation:</u>

We are given the wavelength of the orange light and we are to find the value of its frequency.

Wavelength of orange light = 6.0 \times 10^{-7} m

We know that:

Speed of light = Frequency of orange light × Wavelength of orange light

Substituting the values in the above formula:

3 \times 10^8 = Frequency of orange light × 6.0\times10^{-7}

Frequency of orange light = \frac{3 \times 10^8}{6\times10^{-7}} =5 \times 10^{14} Hz

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Indicate the result of each of the following unit vector cross products (unit vector hat-symbols not shown): . kxi = . jxi= -jxk
notka56 [123]

Answer:

Explanation:

The cross product of two vectors is given by

\overrightarrow{A}\times \overrightarrow{B}=\left | \overrightarrow{A} \right |\left | \overrightarrow{B} \right |Sin\theta \widehat{n}

Where, θ be the angle between the two vectors and \widehat{n} be the unit vector along the direction of cross product of two vectors.

Here, K x i = - j

As K is the unit vector along Z axis, i is the unit vector along X axis and j be the unit vector along  axis.

The direction of cross product of two vectors is given by the right hand palm rule.

So, k x i = j

j x i = - k

- j x k = - i

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3 years ago
An electrician finds that a 1 m length of a certain type of wire has a resistance of 0.24 Ω . What is the total resistance of th
zlopas [31]

The resistance of a given conductor depends on its electrical resistivity (\rho), its length(L) and its cross-sectional area (A), as follows:

R=\frac{\rho L}{A}

In this case, we have L'=138L, \rho'=\rho and A'=A. So, the total resistance of the wire with length of 138m is:

R'=\frac{\rho' L'}{A'}\\R'=\frac{\rho 138L}{A}\\R'=138\frac{\rho L}{A}\\R'=138R\\R'=138(0.24\Omega)\\R'=33.12\Omega

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3 years ago
Please help!!!!!!!!!
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In an Internal Combustion Engine, the fuel is singed in the chamber or vessel. Example: Diesel or Petrol motor utilized as a part of Cars. 
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5 0
3 years ago
Q1: A runner is jogging in a straight line at a steady vr= 6.8 km/hr. When the runner is L= 2.4 km from the finish line, a bird
serious [3.7K]

Answer:

Q1: 3.2km

Q2: 4.8K

Explanation:

Q1:

So db is the distance of bird, and dr is the distance of runner

db = 2vr  and the distance of bird is going to be 2 times greater than the runner.

formulas: db = 2vr & db = 2dr

  1. db = 2dr
  2. L + (L - x) = 2x
  3. 2L - x = 2x
  4. 2L = 3x
  5. x = \frac{2}{3}L

Insert it in x = \frac{2}{3}L

\frac{2}{3}(2.4km) = 1.6km

Now we use formula db = 2dr

  1. db = 2L - x
  2. db = 2(2.4km) - 1.6km
  3. <u>db = 3.2km</u>

Q2:

Formulas: Vr = L /Δt & Vb = db/Δt

  1. Vr = L/ Δt ⇒ Δt = \frac{L}{Vr}
  2. \frac{2.4km}{6.8km/hr}
  3. \frac{6}{17}hr

(Km cancel each other)

  1. Vb = db/Δt ⇒ db = VbΔt
  2. 13.6km/hr(\frac{6}{17}hr )
  3. <u>4.8km</u>

(hr cancel each other)

Hope it helps you :)

6 0
3 years ago
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