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Mice21 [21]
3 years ago
15

How many atoms are in 20.6 moles of curium

Chemistry
1 answer:
Harman [31]3 years ago
4 0

Answer: 1.24 × 10^25

Explanation:

\frac{20.6 moles}{1} × \frac{6.022 * 10^{24} }{1 Mole}

Using our knowledge in unit conversions, we know the mole units cancel each other out and all there's left is the atom unit. From here we can multiply the fractions and eventually we end with the number 124.0532 × 10^23

According to the scientific notation rules, the number to the left of the decimal cannot exceed 10 so we have to move the decimal to the left two spaces. With this change, we also have to change the exponent of the 10. Because we moved the decimal point two spaces to the left, that means we have 10^25.

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Charra [1.4K]
Becky's speed is her distance travelled which is 30 km divided by her time travelled of 2.5 hours which gives her average speed of 12 km/hour which is a quite good speed if she was say riding a bicycle and which would give her a good aerobic workout. 
4 0
3 years ago
Silver is a white metal that is an excellent conductor. Silver tarnishes when exposed to air and light. The density of silver is
Stells [14]

Answer:

c tarnishes in air

Explanation:

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3 0
3 years ago
Read 2 more answers
CH3OH can be synthesized by the reaction:
Leviafan [203]

Answer:

5

Explanation:

8 0
3 years ago
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
How to balance this equation in chemistry
saveliy_v [14]

Answer:

4NH₃(g) +3O₂(g) ⇒2N₂(g) +6H₂O(g)

Explanation:

4 0
3 years ago
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