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Dovator [93]
2 years ago
13

2

Physics
1 answer:
Delvig [45]2 years ago
5 0

The correct option is A. the isobaric process represented by the PV diagram

<h3>What is  isobaric process?</h3>
  • An Isobaric method is a thermodynamic revolution taking place at consistent pressure. The period isobaric has been derived from the Greek words “iso” and “baros” indicating equal intimidation.
  • As such, the continued pressure is obtained when the importance is expanded or acquired. This basically neutralizes any pressure change due to the transfer of heat.
  • In an isobaric procedure, when the heat is transferred to the system some work is done. Nevertheless, there is even a change in the internal energy of the system.
  • This additionally means that no amounts as in the first law of thermodynamics evolve zero.

To learn more about isobaric process, refer to:

brainly.com/question/13040268

#SPJ9

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A string with a mass of 0.034 kg has a length of 4.80 m. If the tension in the string is 100.00 N and a sinusoidal wave with an
GaryK [48]

Explanation:

Below is an attachment containing the solution.

4 0
3 years ago
Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t
Andre45 [30]

Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

g=\frac{GM}{R^2}=9.70 m/s^2

where G is the gravitational constant

M is the Earth's mass

R=6378km = 6.378 \cdot 10^6 m is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg

The Earth's volume is (approximating the Earth to a perfect sphere)

V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3

So, the average density of the Earth is

\rho = \frac{M}{V}=\frac{5.98\cdot 10^{24} kg}{1.087\cdot 10^{21} m^3}=5501 kg/m^3

4 0
4 years ago
Read 2 more answers
How do machines increase mechanical advantage?
Kryger [21]
Mechanical advantage is a measure of the force amplification achieved by using a tool.
7 0
4 years ago
Can someone please here me I’m confused
Naddika [18.5K]
I would say z, x, y, w
5 0
4 years ago
The distance between Earth and Mars is 225 million km. When converted using the conversion factor 1 AU = 1.5 × 108 km, the dista
SIZIF [17.4K]
I guess the problem is asking for the distance between Earth and Mars in Astronomical Units (AU).

Since 1 AU = 1.5 \cdot 10^8 km
and the distance between the two planets is
d=225 mil. km= 2.25 \cdot 10^8 km
we can convert this distance into AU by using the following proportion:
1 AU : 1.5 \cdot 10^8 km = x : 2.25 \cdot 10^8 km

from which we find
x= \frac{1 AU \cdot 2.25 \cdot 10^8 km}{1.5 \cdot 10^8 km} =1.5 AU
7 0
3 years ago
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