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2 years ago

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The basic barometer can be used as an altitude-measuring device in airplanes. The ground control reports a barometric reading of

753 mmHg while the pilot's reading is 690 mmHg. Estimate the altitude of the plane from ground level if the average air density is 1.20 kg/m

1 answer:

kipiarov [429]2 years ago

7 0

Answer:

Δh_air=714m

Explanation:

Given data

$P_{1}=753mmHg\\P_{2}=690mmHg\\ p_{air}=1.2kg/m^{3}\\ g=9.8m/s^{2}$

Solution

ΔP=P₁-P₂

=(ΔhHg)×pHg×g

=(Δh_air)× p_air ×g

Then

Δh_air=(pHg+ΔhHg)÷p_air

$=\frac{13600*(753-690)*10^{-3} }{1.2}\\ =714m$

Δh_air=714m

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Answer:

The correct solution is:

(a) $1.375\times 10^{-2} \ J$

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Explanation:

The given values are:

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Average voltage,

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Now,

(a)

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(b)

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On substituting the values, we get

⇒ $=\frac{1.375\times 10^{-2}}{3.1}$

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(c)

⇒ $C=\frac{Q}{V}$

⇒ $=\frac{4.43\times 10^{-3}}{3.1}$

⇒ $=1.42\times 10^{-3} \ F$

(d)

As we know,

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⇒ $=\frac{1000}{5.6}$

⇒ $=178.57 \ \Omega$

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Answer:

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