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alisha [4.7K]
3 years ago
6

The force between two charges separated by a certain distance is 12 N. What is the force when the distance is doubled?

Physics
1 answer:
salantis [7]3 years ago
7 0

Answer:

Explanation:

its (a) please trust

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Is electrical conductivity?
expeople1 [14]

Answer:

can't tell if this is question, it is not written correctly

Explanation:

Electrical conductivity is the measure of a material's ability to allow the transport of an electric charge. Its SI is the siemens per meter, (A2s3m−3kg−1) (named after Werner von Siemens) or, more simply, Sm−1. It is the ratio of the current density to the electric field strength.

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3 years ago
2. A Zambia police car traveling at 25 m/s slows down at a rate of at 3.5 m/s
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dtuj,kn,jgdjgyhf.jhfv.ku

Explanation:

8 0
3 years ago
Which of the following conditions will drive the equilibrium of the Fischer esterification towards ester formation? A) addition
Lana71 [14]
Both B and D I thinks soo
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3 years ago
A car is moving at a constant speed of 14 m/s when the driver presses down on the gas pedal and accelerates for 14 s with an acc
Vinil7 [7]

acceleration of car is 1.8 m/s^2

time = 14 s

initial speed = 14 m/s

so the final speed is calculated by

v_f = v_i + at

v_f = 14 + 14 * 1.8

v_f = 39.2 m/s

so the total distance moved in this interval of time is

d = \frac{v_f + v_i}{2}* t

d = \frac{39.2 + 14}{2}* 14

d = 372.4 m

now the average speed is given as

v = \frac{d}{t}

v = \frac{372.4}{14}

v = 26.6 m/s

so the average speed will be 26.6 m/s

7 0
3 years ago
The eye of the Atlantic giant squid has a diameter of 3.50 × 10^2 mm. If the eye
Lunna [17]

Answer:

   q = 224 mm,   h ’= - 98 mm, real imagen

Explanation:

For this exercise let's use the constructor equation

        \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

       

where f is the focal length, p and q are the distance to the object and the image respectively.

In a mirror the focal length is

        f = R / 2

indicate us radius of curvature is equal to the diameter of the eye

       R = 3,50  10² mm

       f = 3.50 10² /2 = 1.75 10² mm

they also say that the distance to the object is p = 0.800 10³ mm

        1 / q = 1 / f - 1 / p

        1 / q = 1 / 175 - 1 /800

        1 / q = 0.004464

         q = 224 mm

to calculate the size let's use the magnification ratio

          m = \frac{h'}{h} = - \frac{q}{p}

          h '= - \frac{q}{p} \ h

          h ’= - 224 350 / 800

          h ’= - 98 mm

in concave mirrors the image is real.

3 0
3 years ago
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