Answer: Possible life in non earthlike environments.
Explanation: As per the information provided in the question, the microbe located in California's Lake Mono has a variation in the shape of its DNA as they use arsenic ( if phosphorous was once no longer available) to comprise in the nucleotides of their DNA.
This shows the possibility of life structure in the non-earth-like environment because existence types that originated on earth like environment possess carbon, nitrogen, oxygen, and phosphorous ( that is composed of four fundamental elements).
But existence can additionally be shaped in an environment that lacks phosphorous ( for instance, DNA shaped in microbes utilized arsenic in absence of phosphorous, indicating version in their structure).
Answer:
The circulatory system is the transport system for endocrine info. The endocrine chemicals and hormones must circulate through the body via blood vessels.
Answer:
Evolution is the process that allows the appearance and elaboration of signals, but the key question is: what selective forces led - and lead - to the appearance of color characteristics and chromatic patterns ?, not only in the scope of a species concrete - such as the black bib of the common sparrow (Passer domesticus) - but also within each family or even within a wider framework, for example the light colored spots that we see in the outer feathers of the tail of the bird species Dr. Senar explains the methods and results of the experiments performed so that the reader can compare their interpretation with the scientific advocacy, but also involve other alternative hypotheses. For example, the supposed signals of dominance Do they represent correlations with age and sex, which in turn correlate with dominance? And what can we say about deception, of those signs that exaggerate the status of an individual? The presentation of the different alternatives offers the reader the opportunity to detect the complexity of the selective forces and the difficulty of designing clear and conclusive experiments. In a similar way, the author presents the multiple hypotheses that address sexual selection and delayed maturation of plumage, thus facilitating the reader, understanding of the different topics discussed and a better appreciation of the elegant experiments that have been used to formulate and defend some of these hypotheses. Camouflage is treated in a separate chapter, but Dr. Senar not only focuses on the colors of the prey, which affects the object of investigations, but also on the color of predators, whose study has been the subject of much attention minor The interpretation of color as a bioindicator is an innovative approach that is proposed towards the end of the book. This is the first time that this possibility was raised, but, as the author points out, if the birds determine the quality of the habitat by the color of the potential couple that lives in it, there is no doubt that we should also be able to determine the quality of a habitat using similar means. Experiments that allow us to evaluate this approach are described throughout the book.
<span>Discontinue the transfusion and begin an infusion of normal saline.</span>
First we must understand the balanced chemical equation:
Pb(NO3)2 + K2CrO4 ==> PbCr04 + 2KNO3
This shows us that two moles of potassium nitrate are formed from 1 mole of lead nitrate or potassium chromate solution. The next step is to find out how many moles of each reactant there are. Note the word Molar is a concentration that simply means moles per liter.
2.25L of 1.5M lead nitrate = 2.25x1.5 = 3.375 moles of lead nitrate
1.15L of 2.75M potassium chromate = 1.15x2.75 = 3.1625 moles
The important part here is to see that the number of moles of the reactants are different. We know the number of moles of products will be dependent on the number of moles of reactants, and in this case there is less potassium chromate than there is lead nitrate, so this is the limiting factor as there is a one to one relationship with both reactants. Therefore, the number of moles of potassium nitrate produced is 2 x number of moles of potassium chromate. i.e. 6.325 moles of potassium nitrate is liberated.
To work out the number of grams, we must find the molar mass (the mass of one mole) of KNO3, which is the sum of the molar mass of each of its component atoms that make up the molecule. I've looked this up as 101.1 grams per mole.
Now we simply times the molar mass by the number of moles to yield the final grams liberated: 6.325 moles x 101.1 grams/mole = 639.4 grams of potassium nitrate is liberated from this reaction.
