To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,
The circumference of the planet is,
Under the mathematical value the radius would be
Using second equation of motion
Replacing the values given,
Rearranging and solving for 'a' we have,
Using the value of acceleration due to gravity from Newton's law we have that
Here,
r = Radius of the planet
G = Gravitational Universal constant
M = Mass of the Planet
Therefore the mass of this planet is
Answer: the reaction
Explanation: it’s the only answer that is the result
Answer:
The number is
Explanation:
From the question we are told that
The wavelength is
The length of the glass plates is
The distance between the plates (radius of wire ) =
Generally the condition for constructive interference in a film is mathematically represented as
Where t is the thickness of the separation between the glass i.e
t = 0 at the edge where the glasses are touching each other and
t = 2d at the edge where the glasses are separated by the wire
m is the order of the fringe it starts from 0, 1 , 2 ...
So
=>
=>
given that we start counting m from zero
it means that the number of bright fringes that would appear is
=>
=>
Answer:
The reach of the tongue is 23 cm.
Explanation:
Hi there!
The equation of traveled distance is the following:
x = x0 + v0 · t + 1/2 · a · t²
Where:
x = traveled distance at time t.
x0 = initial position.
v0 = initial velocity.
a = acceleration.
t = time.
Let´s calculate the distance traveled by the tongue of the chameleon during the first 20 ms (0.020 s):
The initial position and velocity are zero (x0 = 0 and v0 = 0)
x = 1/2 · a · t²
x = 1/2 · 280 m/s² · (0.020 s)²
x = 0.056 m
Now, let´s find the distance traveled while the tongue moves at constant speed. But first, let´s find the velocity (v) of the tongue after the accelertation interval using the following equation:
v = v0 + a · t (v0 = 0)
v = 280 m/s² · 0.020 s
v = 5.6 m/s
Then, the distance traveled at constant speed can be calculated:
x = v · t
x = 5.6 m/s · 0.030 s
x = 0.17 m
The reach of the tongue is 0.17 m + 0.056 m = 0.23 m = 23 cm.