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NNADVOKAT [17]
3 years ago
8

Who was the first who traveled to the moon?​

Physics
2 answers:
slava [35]3 years ago
8 0

NEIL ARMSTRONG WAS THE FIRST MAN WHO TRAVELLED TO THE MOON.

soldi70 [24.7K]3 years ago
8 0

Answer:

On July 20, 1969, Neil Armstrong became the first human to step on the moon. 

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ehidna [41]

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The risk of earthquakes is high along the Pacific coast of the United States because a. There have been no earthquakes there lat
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(D) That's where the Pacific and North American plates meet.
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3 years ago
If a steady magnetic field exerts a force on a moving charge, that force is directed
lesya [120]

Answer:

C) at right angles to the direction of the motion

Explanation:

The magnetic force exerted on a charged moving particle is given by

F=qvBsin \theta

where

q is the charge of the particle

v is the velocity of the particle

B is the magnetic field intensity

\theta is the angle between the direction of v and B

Moreover, the direction of the force is perpendicular to both v and B. In particular, the direction can be found by using the right hand rule:

- index finger: direction of the velocity

- middle finger: direction of the magnetic field

- thumb: direction of the force (if the charge is positive, otherwise the direction must be reversed if the charge is negative)

4 0
3 years ago
A 9­v battery is connected to a light bulb with a resistance of 3?. what is the current in the circuit
anygoal [31]
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7 0
3 years ago
A certain atom has atomic number Z = 25 and atomic mass number A = 52. a. What is the approximate radius of the nucleus of this
wlad13 [49]

Answer:

a)The approximate radius of the nucleus of this atom is 4.656 fermi.

b) The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

Explanation:

r=r_o\times A^{\frac{1}{3}}

r_o=1.25 \times 10^{-15} m = Constant for all nuclei

r = Radius of the nucleus

A = Number of nucleons

a) Given atomic number of an element = 25

Atomic mass or nucleon number = 52

r=1.25 \times 10^{-15} m\times (52)^{\frac{1}{3}}

r=4.6656\times 10^{-15} m=4.6656 fm

The approximate radius of the nucleus of this atom is 4.656 fermi.

b) F=k\times \frac{q_1q_2}{a^2}

k=9\times 10^9 N m^2/C^2 = Coulombs constant

q_1,q_2 = charges kept at distance 'a' from each other

F = electrostatic force between charges

q_1=+1.602\times 10^{-19} C

q_2=+1.602\times 10^{-19} C

Force of repulsion between two protons on opposite sides of the diameter

a=2\times r=2\times 4.6656\times 10^{-15} m=9.3312\times 10^{-15} m

F=9\times 10^9 N m^2/C^2\times \frac{(+1.602\times 10^{-19} C)\times (+1.602\times 10^{-19} C)}{(9.3312\times 10^{-15} m)^2}

F=2.6527 N

The electrostatic force of repulsion between two protons on opposite sides of the diameter of the nucleus is 2.6527

6 0
3 years ago
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