Answer:
x = 45 cm
Explanation:
Given that,
The length of a rod, L = 50 cm
Mass, m₁ = 0.2 kg
It is at 40cm from the left end of the rod.
We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.
The centre of mass of the rod is at 25 cm.
Taking moments of both masses such that,
![15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm](https://tex.z-dn.net/?f=15%5Ctimes%200.2%3Dx%5Ctimes%200.6%5C%5C%5C%5Cx%3D%5Cdrac%7B3%7D%7B0.6%7D%5C%5C%5C%5Cx%3D5%5C%20cm)
The distance from the left end is 40+5 = 45 cm.
Hence, at a distance of 45 cm from the left end it will balance the rod.
Answer:
![q = 2.067 \times 10^{-5}\ C](https://tex.z-dn.net/?f=q%20%3D%202.067%20%5Ctimes%2010%5E%7B-5%7D%5C%20C)
Explanation:
Given,
mass = 1.41 g = 0.00141 Kg
Electric field,E = 670 N/C.
We know,
Force in charge due to Electric field.
F = E q
And also we know
F = m g
Equating both the equation of motion
m g = E q
![q = 2.067 \times 10^{-5}\ C](https://tex.z-dn.net/?f=q%20%3D%202.067%20%5Ctimes%2010%5E%7B-5%7D%5C%20C)
Charge of the particle is equal to ![q = 2.067 \times 10^{-5}\ C](https://tex.z-dn.net/?f=q%20%3D%202.067%20%5Ctimes%2010%5E%7B-5%7D%5C%20C)
Answer:
(a) 2.34 s
(b) 6.71 m
(c) 38.35 m
(d) 20 m/s
Explanation:
u = 20 m/s, theta = 35 degree
(a) The formula for the time of flight is given by
![T = \frac{2 u Sin\theta }{g}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%20u%20Sin%5Ctheta%20%7D%7Bg%7D)
![T = \frac{2 \times 20 \times Sin35 }{9.8}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%20%5Ctimes%2020%20%5Ctimes%20Sin35%20%7D%7B9.8%7D)
T = 2.34 second
(b) The formula for the maximum height is given by
![H = \frac{u^{2} \times Sin^{2}\theta }{2g}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7Bu%5E%7B2%7D%20%5Ctimes%20Sin%5E%7B2%7D%5Ctheta%20%7D%7B2g%7D)
![H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7B20%5E%7B2%7D%20%5Ctimes%20Sin%5E%7B2%7D35%20%7D%7B2%20%5Ctimes%209.8%7D)
H = 6.71 m
(c) The formula for the range is given by
![R = \frac{u^{2} \times Sin 2\theta }{g}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7Bu%5E%7B2%7D%20%5Ctimes%20Sin%202%5Ctheta%20%7D%7Bg%7D)
![R = \frac{20^{2} \times Sin 2 \times 35}{9.8}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7B20%5E%7B2%7D%20%5Ctimes%20Sin%202%20%5Ctimes%2035%7D%7B9.8%7D)
R = 38.35 m
(d) It hits with the same speed at the initial speed.
Two Factors That Affect How Much Gravity Is on an Object. Gravity is the force that gives weight to objects and causes them to fall to the ground when dropped. Two major factors, mass and distance, affect the strength of gravitational force on an object.
Hi there!
Informative writing has the intent to inform or educate us on a particular topic or event. It gives us more information and insight onto something.
Persuasive writing has the intent of convincing us to believe in a certain idea or to perform a certain action. For instance, advertisements have a persuasive intent; they are persuading us to buy a product or service.
Argumentative writing is similar to persuasive writing in the sense that they are persuading us to believe a certain idea. However, they are often based on logic and fact rather than opinions.
Let's look at the first excerpt.
<em>This morning at 9 a.m., a school bus collided with a car at the intersection of Osmena and Cabrera streets. The passengers were not injured, but the medical personnel checked each student as well as the driver before they were transported to their school.</em>
This text doesn't try to convince us in believing something. It doesn't argue anything and it only tries to give us more insight onto the event, which is a car accident. No opinions are stated and only events are given.
Therefore, this excerpt uses an informative writing technique.