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zvonat [6]
3 years ago
15

If you run at 8m/s for 15 minutes how far will you go

Physics
2 answers:
enyata [817]3 years ago
8 0

Answer:

<h2>hope it helps you see the attachment for further information ......✌✌✌✌✌</h2>

sashaice [31]3 years ago
6 0

Answer: 7200 m

Explanation: The solution is, first convert 15 minutes to seconds.

15 mins x 60 s / 1 min = 900 s

Use the formula for speed which is v= d/t then derive for d.

d = vt

= 8 m/s ( 900s)

= 7200 m

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Newton's 3rd Law is based on what type of forces?
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Read 2 more answers
A person who weighs 800N on the earths surface will weigh 200N at what height above the earth
mote1985 [20]

Answer: 6,400 km

Explanation:

The weight of a person is given by:

W=mg

where m is the mass of the person and g is the acceleration due to gravity. While the mass does not depend on the height above the surface, the value of g does, following the formula:

g=\frac{GM}{r^2}

where

G is the gravitational constant

M is the Earth's mass

r is the distance of the person from the Earth's center


The problem says that the person weighs 800 N at the Earth's surface, so when r=R (Earth's radius):

800 N= W=mg=m \frac{GM}{R^2} (1)

Now we want to find the height h above the surface at which the weight of the man is 200 N:

200 N = W' = mg' = m \frac{GM}{(R+h)^2} (2)

If we divide eq.(1) by eq.(2), we get

\frac{800 N}{200 N}=\frac{W}{W'}=\frac{(R+h)^2}{R^2}

4=\frac{(R+h)^2}{R^2}

By solving the equation, we find:

4R^2 = (R+h)^2=R^2+2Rh+h^2\\h^2 +2Rh-3R^2 =0

which has two solutions:

h=-3R --> negative solution, we can ignore it

h=R --> this is our solution

Since the Earth's radius is R=6.4\cdot 10^6 m, the person should be at h=R=6.4\cdot 10^6 m=6400 km above Earth's surface.

7 0
3 years ago
A spring (k = 790 N/m) has a length of 48 cm when zero net force is applied to it. What will its length be when 230 N of force i
timama [110]

Answer:

0·77 m

Explanation:

Given

Spring constant = k = 790 N/m

Equilibrium length of the spring = 48 cm = 0·48 m

Force applied = 230 N

Let the x m be the length of the spring when 230 N of force is applied on it

Spring force that is acting will be k × (x - 0·48)

<h3>Because spring force that is acting will be proportional to length from the equilibrium position</h3>

When applied force is 230 N, the spring force will also be equal to 230 N as there will be equilibrium

∴ k × (x - 0·48) = 230

790 × (x - 0·48) = 230

x = (230 ÷ 790) + 0·48

x = 0·29 + 0·48

∴ x = 0·77 m

∴ Length of the spring when 230 N of force is applied to stretch it = 0·77 m

3 0
3 years ago
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