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andrey2020 [161]
3 years ago
11

What is an example of a stable system

Physics
2 answers:
oksian1 [2.3K]3 years ago
6 0
Some examples of stable system are:

1) functions of sine

2) DC

3) signum

4) unit step 

5) cosine.

Happy Studying! ^^


NNADVOKAT [17]3 years ago
3 0
The cosine is an example of a stable system.

Hope this helps !
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A fireboat is to fight fires at coastal areas by drawing seawater with a density of 1030 kg/m3 through a 10-cm-diameter pipe at
GaryK [48]

Answer:

50.93 m/s

199.5 kW

Explanation:

From the question, the nozzle exit diameter = 5 cm, Radius= diameter/2= 5cm/2= 2.5cm. we can convert it to metre for unit consistency= (2.5×0.01)=

0.025m

We can calculate the The cross sectional area of the nozzle as

A= πr^2

A= π ×0.025^2

= 1.9635 ×10^- ³ m²

From the question, the water is moving through the pipe at a rate of 0.1 m /s , then for the water to move through it at a seconds, it must move at

(0.1 / 1.9635 ×10^- ³ m²)

= 50.93 m/s

During the Operation of the pump, the Dynamic energy of the water= potential energy provided there is no loss during the Operation

mgh = 1/2mv²

We can make "h" subject of the formula, which is the height of required head of water

h = (1/2mv²)/mg

h= v² / 2g

h = 50.93² / (2 ×9.81)

h = 132.21m

From the question;

The total irreversible head loss of the system = 3 m,

the given position of nozzle = 3 m

the total head the pump needed=(The total irreversible head loss of the system + the position of the nozzle + required head of water )

=(3 + 3 + 132.21m)

=138.21m

mass of water pumped in a seconds can be calculated since we know that mass is a product of volume and density

Volume= 0.1m³

Density of sea water=1030 kg/m

(0.1 m^3× 1030)

= 103kg

We can calculate the Potential enegry, which is = mgh

= (103 ×9.81 × 138.21)

= 139651.5 Watts

= 139.65kW

To determine required shaft power input to the pump and the water discharge velocity

Energy= efficiency × power

But we are given efficiency of 70 percent, then

139651.5 Watts = 0.7P

=199502.18 Watts

P=199.5 kW

Therefore, the required shaft power input to the pump and the water discharge velocity is 199.5 kW

5 0
2 years ago
Greg is in a bike race. at mile marker four (out of ten), his speed was measured at 13.5 mph. which best describes the measured
posledela
The instantaneous speed. 
3 0
3 years ago
Read 2 more answers
Which statement is correct?
miv72 [106K]
'A' is correct. B, C, and D are false statements.
5 0
3 years ago
Read 2 more answers
If a sled has at the top of 10 m hill had 1000 J of potential energy what would happen to the PE if the sled were to moved to a
nataly862011 [7]

Answer:

500J

Explanation:

there are many students who can not get answer step by step and in required time. so

there are a wats group where you can get your answer by trusted experts.

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7 0
3 years ago
An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the
andrew-mc [135]

Answer:

50 W

Explanation:

Case 1

Power = V * I

100 = 220 * I

I = \frac{100}{220} A

Case 2

P = V * I

P = 110 * \frac{100}{220}

P = 50 W

I think the answer is 50 W

Hope it helps

8 0
3 years ago
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