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Tanya [424]
3 years ago
13

At maximum height, the velocity is zero.

Physics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer:

True

Explanation:

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HELP!!!!!! Need Help !!!
denis23 [38]

Answer:

its y

Explanation:

3 0
3 years ago
An observer is standing next to the tracks, watching a train approach. The train travels at 30 m/s and blows its whistle at 8,00
SSSSS [86.1K]

7351.35Hz

f0= v-Vo/v-Vs × FSA

= 340-0 /340+30 ×8000

= 340/370× 8000

= 7351.35hz

7 0
3 years ago
In which mechanical test is a specimen deformed with a gradually increasing load that is applied uniaxially along the long axis
IRINA_888 [86]

Answer:

Compression Test

Explanation:

The Specimen is undergoing a compression test. It is similar to tensile test with the difference that the force is compressive and applied along the direction of stress. Both Tensile and compression tests are performed on Universal Testing machine. Compression test is done to determine the product's reaction when it is compressed, squashed and crushed.

7 0
3 years ago
A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the buildi
solniwko [45]

Answer:

32.3 m/s

Explanation:

The ball follows a projectile motion, where:

- The horizontal motion is a uniform motion at costant speed

- The vertical motion is a free fall motion (constant acceleration)

We start by analyzing the horizontal motion. The ball travels horizontally at constant speed of

v_x = 50 m/s

and it covers a distance of

d = 165 m

So, the total time of flight of the ball is

t=\frac{d}{v_x}=\frac{165}{50}=3.3 s

In order to find the vertical velocity of the ball, we have now to analyze its vertical motion.

The vertical motion is a free-fall motion, so the ball is falling at constant acceleration; therefore we can use the following suvat equation:

v_y = u_y +at

where

v_y is the vertical velocity at time t

u_y=0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration  of gravity (taking downward as positive direction)

Substituting t = 3.3 s (the time of flight), we find the final vertical velocity of the ball:

v=0 + (9.8)(3.3)=32.3 m/s

5 0
3 years ago
A body is accelerated continuously. What is the form of the graph?
Inga [223]
That depends on what quantity is graphed.

It also depends on what kind of acceleration is taking place ...
continuous change of speed or continuous change of direction.

-- If the graph shows speed vs time, and the acceleration is a change
in speed, then the graph is a connected series of straight-line pieces. 
Each straight piece slopes up if speed is increasing, or down if speed
is decreasing.

-- If the graph shows speed vs time, and the acceleration is a change in
direction only, then the graph is a straight horizontal line, since speed is
constant.

-- If the graph shows direction vs time, and the acceleration is a change
in speed only, then the graph is a straight horizontal line, since direction
is constant.

-- If the graph shows direction vs time, and the acceleration is a change
in direction, then the graph is a connected series of pieces of line. 
Each piece may be straight if the direction is changing at a constant rate,
or curved if the direction is changing at a rate which grows or shrinks. 
Each piece may slope up if the angle that defines the direction is growing,
or may slope down if the angle that defines the direction is decreasing.

-- If the graph shows distance vs time, and the acceleration is a
change in speed, then the graph is a connected series of pieces
of curves.  Each piece curves up if speed is increasing, or down if
speed is decreasing.

-- If the graph shows distance vs time, and the acceleration is a change
in direction only, then the graph is a straight line sloping up, since speed
is constant.

6 0
3 years ago
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