Distance of lake a is 200 km at 20 degree north of east
distance between lake a and b is 230 km at 30 degree west of north
now the distance between base and lake b is given as

given that




now the total distance is


now the magnitude of the distance is given as


also the direction is given as


<em>so it is 277.4 km at 74.7 degree North of East</em>
Answer:
Plate separation of each capacitor is 101.132 °A
Explanation:
The formula to calculate the capacitance in empty space as a function of distance (square parallel plates) is:

clearing for distance:

It is based on their state like population, literacy and poverty it varies from state to state, country to country
Answer:
angular range is ( 0.681 rad , 0.35 rad )
Explanation:
given data
wavelength λ = 380 nm = 380 ×
m
wavelength λ = 700 nm = 700 ×
m
to find out
angular range of the first-order
solution
we will apply here slit experiment equation that is
d sinθ = m λ ...........1
here m is 1 for single slit and d is = 
so put here value in equation 1 for 380 nm
we get
d sinθ = m λ
sinθ = 1 × 380 × 
θ = 0.35 rad
and for 700 nm
we get
d sinθ = m λ
sinθ = 1 × 700 × 
θ = 0.681 rad
so angular range is ( 0.681 rad , 0.35 rad )
Answer: Electromagnetic radiation
Explanation:
Electromagnetic radiation is a combination of oscillating electric and magnetic fields, which propagate through space carrying energy from one place to another.
To understand it better:
This radiation is spread thanks to the electromagnetic fields produced by moving electric charges and their sources can be natural or man-made.
It should be noted that the energy of electromagnetic radiation can vary and depending on its frequency it can be useful for various situations.