When a 3.0 N weight is attached to a vertical coil spring, it stretches 5.0 cm. What weight would be required to stretch the spr ing 12.5 cm?
1 answer:
The weight required to stretch the spring 12.5 cm is 7.5 N ( Option A )
<h3>Data obtained from the question</h3>
Initial weight (W₁) = 3 N Initial Length (L₁) = 5 cm New length (L₂) = 12.5 cm New Weight (W₂) =?
<h3>How to determine the new weight </h3>
The new weight required to stretch the spring can be obtained as follow:
W₁ / L₁ = W₂ / L₂
3 / 5 = W₂ / 12.5
Cross multiply
W₂ × 5 = 3 × 12.5
Divide both sides by 5
W₂ = (3 × 12.5) / 5
W₂ = 7 . 5 N
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