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nirvana33 [79]
2 years ago
9

When a 3.0 N weight is attached to a vertical coil spring, it stretches 5.0 cm. What weight would be required to stretch the spr

ing 12.5 cm?
Group of answer choices

a. 7.5 N

b. 15 N

c. 4.5 N

d. 1.2 N
Physics
1 answer:
Mademuasel [1]2 years ago
6 0

The weight required to stretch the spring 12.5 cm is 7.5 N (Option A)

<h3>Data obtained from the question</h3>
  • Initial weight (W₁) = 3 N
  • Initial Length (L₁) = 5 cm
  • New length (L₂) = 12.5 cm
  • New Weight (W₂) =?

<h3>How to determine the new weight </h3>

The new weight required to stretch the spring can be obtained as follow:

W₁ / L₁ = W₂ / L₂

3 / 5 = W₂ / 12.5

Cross multiply

W₂ × 5 = 3 × 12.5

Divide both sides by 5

W₂ = (3 × 12.5) / 5

W₂ = 7.5 N

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

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