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2 years ago

A 250 kg cart is at the top of a hill that is 32 m high, what is its potential energy?

Physics

1 answer:

atroni [7]2 years ago

3 0

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 250 × 10 × 32

We have the final answer as

Hope this helps you

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The next closest star to Earth, Proxima Centuri, is 4.25 lightyears away. How far is that in meters?

lozanna [386]

Answer:

4.0208 x 10^16 meters

Explanation:

speed of light in m/s * # seconds in a year * 4.25 years =

2.99792 x 10^8 * 3600*24*365.25 * 4.25 = 4.0208 x 10^16 m

8 0

2 years ago

A 10 g bullet moving horizontally with a speed of 2000 m/s strikes and passes through a 4.0 kg block moving with a speed of 4.2

Masteriza [31]

Answer:

The answer is "512 J".

Explanation:

bullet mass $m_1 = 10 g= 10^{-2} \ kg\\\\$

initial speed $u_1 = 2\ \frac{Km}{s}= 2000\ \frac{m}{s}\\\\$

block mass $m_2 = 4\ Kg$

initial speed $v_2 =-4.2 \frac{m}{s}$

final speed $v_2= 0$

Let $v_1$ will be the bullet speed after collision:

throughout the consevation the linear moemuntum

$\to M_1V_1+m_2v_2=M_1U_1+m_2u_2\\\\\to (10^{-2} kg) V_1 +0 = (10^{-2} kg)(2000 \frac{m}{s}) + (4 \ kg)(-4.2 \frac{m}{s}) \\\\\ \to 10^{-2} v_1 = 20 -16.8\\\\$

$= 320 \frac{m}{s}$

The kinetic energy of the bullet in its emerges from the block

$k=\frac{1}{2} m_1 v_1^2$

$=\frac{1}{2} \times 10^{-2} \times 320\\\\=512 \ J$

3 0

2 years ago

If copper (E⁰ = ⁺0.34) and lithium (E⁰ = ⁻3.05) are used to make a battery, will electrons flow from lithium to copper or vice v

Lemur [1.5K]

Answer:

give me brainliest first and ill give u the correct anwers

Explanation:

4 0

2 years ago

What is the kinetic energy of a 0.5 kg puppy that is running 1.5m/s

bija089 [108]

Answer: Well the answer is KE = 5.625E-7 i just don't know the units for it...

Hope this helps....... Stay safe and have a Merry Christmas!!!!!!!!!! :D

3 0

3 years ago

The static frictional force between a 95-kilogram object and the floor is 45 Newtons. The kinetic frictional force is only 22 Ne

Lisa [10]

Answer:

F = 69.5 [N]

Explanation:

We must remember that the friction force is defined as the product of the normal force by the coefficient of friction, and it can be calculated by the following expression.

$f=N*miu$

where:

N = normal force [N]

miu = friction coefficient

f = friction force = 22 [N]

Now we must calculate the force exerted by means of Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

$F - f = m*a$

where:

F = force exerted [N]

f = friction force [N]

m = mass = 95 [kg]

a = acceleration = 0.5 [m/s²]

Now replacing:

$F - 22 = 95*0.5\\F = 47.5 + 22\\F = 69.5 [N]$

6 0

3 years ago