Question

Hydrogen peroxide is oxidized with permanganate solution to produce oxygen gas by the following reaction:

Answer 1

The percentage yield of the oxygen gas is 60%.

What is the limiting reactant?

The reaction equation is;

2H^+ + H2O2 + 2MnO4 -> 2MnO2 + 4H2O + 3O2

Number of moles of hydrogen peroxide = 30/1000 * 0.30 M = 9 * 10^-3 moles

Number of moles of  potassium permanganate = 30/1000 * 0.30 M = 9 * 10^-3 moles

Now;

1 mole of H2O2 reacts with 2 moles of permanganate

 9 * 10^-3 moles of H2O2 reacts with  9 * 10^-3 moles * 2 moles/1 mole  

= 1.8 * 10^-2 moles

Hence, permanganate is the limiting reactant

b) The theoretical yield of oxygen is;

2 moles of oxygen produced 3 moles of O2

9 * 10^-3 moles oxygen  produced 9 * 10^-3 moles *  3 moles/2 moles

= 0.0135 moles

If 1 mole of O2 occupies 22.4 L

0.0135 moles of O2 occupies 0.0135 moles * 22.4 L/ 1 mole

= 0.302 L or 302 mL

c) Percentage yield of oxygen = 178 mL/ 302 mL * 100/1

= 60%

Learn more about percentage yield:brainly.com/question/27492865

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