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Inessa [10]
3 years ago
7

The La Brea Tar Pits are _______. (multiple choice answers in attached file)

Chemistry
2 answers:
deff fn [24]3 years ago
7 0
The answer is B

Hope this helps
Alekssandra [29.7K]3 years ago
4 0
B filled with made from mammals
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The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K: 2CH2Cl2(g) CH4(g) CCl4(g) Calculate the equilibrium p
Ostrovityanka [42]

The complete question is as follows: The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K: 2CH2Cl2(g) CH4(g) + CCl4(g) Calculate the equilibrium partial pressures of all species when CH2Cl2(g) is introduced into an evacuated flask at a pressure of 0.968 atm at 350 K. PCH2Cl2 = atm PCH4 = atm PCCl4 = atm

Answer: The equilibrium partial pressures of all species, that is, CH_{4}, CCl_{4} and CH_{2}Cl_{2} is 0.420 atm, 0.420 atm and 0.128 atm.

Explanation:

For the given reaction equation, the initial and equilibrium concentration of involved species is as follows.

                       2CH_{2}Cl_{2}(g) \rightarrow CH_{4}(g) + CCl_{4}(g)\\

Initial:                0.968 atm         0               0

Equilibrium:  (0.968 - 2x)           x                x

Now, K_{p} for this reaction is as follows.

K_{p} = \frac{P_{CH_{4}}P_{CCl_{4}}}{P^{2}_{CH_{2}Cl_{2}}}\\10.5 = \frac{x \times x}{(0.968 - 2x)^{2}}\\x = 0.420

P_{CH_{4}} = x = 0.420 atm\\P_{CCl_{4}} = x = 0.420 atm\\P_{CH_{2}Cl_{2}} = (0.968 atm - 2x) = (0.968 atm - 2(0.420)) = 0.128 atm

Thus, we can conclude that the equilibrium partial pressures of all species, that is, CH_{4}, CCl_{4} and CH_{2}Cl_{2} is 0.420 atm, 0.420 atm and 0.128 atm.

3 0
3 years ago
What mass of HCl is neutralized by 3.33 g Mg(OH)2?
postnew [5]
First, you write the balanced equation for the reaction

2HCl + Mg(OH)2 ----->MgCl2 + 2H2O


Next, find the number of moles of Magnesium Hydroxide

Number of moles of Mg(OH)2 =

mass / Mr = 3.33 / 24 +2(1+16)
=0.0574 mol

Find the mole ratio between HCl and Mg(OH)2 which is 1:2

Number of moles of HCl = 0.0574 x 2 = 0.1148 mol

Mass of HCl = Mr x no. of moles
=0.1148 x (1+35.5)
=4.19 g
3 0
3 years ago
A student placed 19.0 g of glucose (c6h12o6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
EleoNora [17]
  <span>moles glucose = 19 g / 180 g/mol= 0.105 
M = 0.105 / 0.100 L = 1.05 

moles in 20.0 mL = 1.05 M x 0.0200 L = 0.0216 

New concentration = 0.0216 /0.500 L = 0.0432 M 
moles in 100 mL = 0.100 L x 0.0432 = 0.00432 

mass = 0.00432 x 180 g/mol= 0.778 g</span>
7 0
3 years ago
Which of the following structers is formed when fertilization occurs
kaheart [24]
I believe the answer would be C
5 0
4 years ago
Each Excedrin tablet contains 250 mg aspirin (ACE), 250 mg of acetaminophen (ACE), and 65 mg of caffeine (CAF). Calculate the th
yawa3891 [41]

Answer:

a) 37.04%  b) 37.04%  c) 9.63%

Explanation:

The theoretical percent recovery (Tr), is the total percentage of each compound in the sample. Depending on the technique used to recovery the compounds, the percent recovery will be less than the theoretical, because no technique is 100% efficient.

So, to calculate the theoretical, it will be the mass of the compound divided by the mass of the sample multiplied by 100%.

a) Tr = (250 mg)/(675 mg) * 100%

Tr = 37.04%

b) Tr = (250 mg)/(675 mg) * 100%

Tr = 37.04%

c) Tr = (65 mg)/(675 mg) * 100%

Tr = 9.63%

3 0
4 years ago
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