Answer:
half life=16.5hrs
sample=2g
total time=1day=24hrs
no. of half lives=total time/half life
no. of half lives=24hrs/16.5hrs=1.45approx1.5
sample left=1/2n=1/2[1.5]=0.707gapprox
Explanation:
Answer:
solubility of X in water at 17.0
is 0.11 g/mL.
Explanation:
Yes, the solubility of X in water at 17.0
can be calculated using the information given.
Let's assume solubility of X in water at 17.0
is y g/mL
The geochemist ultimately got 3.96 g of crystals of X after evaporating the diluted solution made by diluting the 36.0 mL of stock solution.
So, solubility of X in 1 mL of water = y g
Hence, solubility of X in 36.0 mL of water = 36y g
So, 36y = 3.96
or, y =
= 0.11
Hence solubility of X in water at 17.0
is 0.11 g/mL.