Question

A jet of water squirts out horizontally from a hole near the bottom of the tank, as seen in the figure.

Answer 1

The height, h, of the water level in the tank is  mathematically given as

h=1.3675

What is the height, h, of the water level in the tank?

Generally, the equation for kinematics is  mathematically given as

S=v_o t+(1/2)at^2

Therefore

y=0+(1/2)gt^2

Where

t=(2y/g)^{1/2}

t=(2*1.72/9.8)^{1/2}

t=0.5925s

The horizontal exit velocity will be given as

$Vx=x/t$

Therefore

$Vx=\frac{0.3.13}{0.5925}$

Vx=0.5283

In conclusion, applying Bernoulli's Law the tank bottom and tank surface

P+(1/2)pv0^2+pgh=P+(1/2)pvx^2+pgh

(1/2)(p)(0m/s)^2+pgh=(1/2)pvx^2+pg(0m)

gh=(1/2)vx^2

h=(0.5283m/s)^2/(2)(9.8)

h=1.3675

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