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Nimfa-mama [501]

3 years ago

8

A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.2 m/s. The drag force is of the form bv2 What is the value of b?

1 answer:

Bingel [31]3 years ago

8 0

Drag force is a force that resist the motion of a certain body through a fluid like air or water. This can be calculated through the equation,
D = 0.5Cρv²
where D is drag, C is the drag coefficient, ρ is the density and v is the velocity. The value therefore of b in the item above is,
b = 0.5Cρ

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NikAS [45]

Answer:

M = 0.730*m

V = 0.663*v

Explanation:

Data Given:

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Conservation of Momentum:

$P_{initial} = P_{final}\\m*v_{i} = m*0.516v_{i} + M*V\\0.484m*v_{i} = M*V .... Eq1$

Energy Balance:

$\frac{1}{2}*m*v^2_{i} = \frac{1}{2}*m*(0.516v_{i})^2 + \frac{1}{2}*M*V^2 + 0.413*\frac{1}{2}*m*v^2_{i}\\\\0.320744*m*v^2_{i} = M*V^2\\\\M = \frac{0.320744*m*v^2_{i} }{V^2} ....... Eq 2$

Substitute Eq 2 into Eq 1

$0.484*m*v_{i} = \frac{0.320744*m*v^2_{i} }{V^2} *V \\0.484 = 0.320744*\frac{v_{i} }{V} \\\\V = 0.663*v_{i}$

Using Eq 1

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7 0

3 years ago

In moving out of a dormitory at the end of the semester, a student does 1.20 x 104 J of work. In the process, his internal energ

Zielflug [23.3K]

Answer:

(a) W=1.20×10⁴J

(b) U= -5.46×10⁴J

(c) Q= -4.26×10⁴J

Explanation:

Given that student does 1.20×10⁴J work

(a) W=1.20×10⁴J

Work done by student,so positive sign

During the process, his internal energy decreases by 5.46×10⁴J.

(b) U= -5.46×10⁴J.

As the Energy decreases therefore negative sign

For (c) Q

We know the formula

$Q=W+U\\Q=1.2*10^{4}+(-5.46*10^{4} )\\ Q=-4.26*10^{4}J$

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Answer:

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